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Tema [17]
3 years ago
12

If line q has a slope of -3/8 what is the slope of any line perpendicular to q?

Mathematics
1 answer:
kompoz [17]3 years ago
7 0

Answer:

new slope = 4/3

Step-by-step explanation:

-3/8 is perpendicular to the new slope

=> new slope = -8/3 * -1/2

= 8/6

= 4/3

please give me brainliest if it is helpful for you

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Hope this helps :)
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3 years ago
The difference between 33 1/3% and 33%
Luden [163]

Answer:

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3 years ago
Evaluate 5x3 - 21 + 7 when x = -2.
Sliva [168]

Answer:

26

Step-by-step explanation:

5x³ - 21 + 7

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then:

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8 0
3 years ago
Read 2 more answers
Given m||n, find the value of x.<br> kt<br> (7-10)<br> (6x-5)°
Dennis_Churaev [7]

Answer:

15

Step-by-step explanation:

So, leets look at the graph.

We can see that the lines being solved for tecnically make up 180 degrees.

This is because the value of the angles on line m are equal to the value of the angles on line n.

So, we know that the total line, 180 degrees, is 7x-10, and 6x-5.

Lets combine these two equations, and subtract them from 180 degrees to solve for x:

7x-1+6x-5

=

13x-15

Now to solve for x:

13x-15=180

Add 15 to both sides to get 13x alone:

13x=195

Then divide both sides by 13 to get x alone:

x=15

So our value of x is 15!

Hope this helps! :)

3 0
2 years ago
Evaluate: cos ω, if tan ω = - 4/3 and sin ω &gt; 0
polet [3.4K]

Answer:

-3/5

Step-by-step explanation:

tan = opp/adj using pathagorean the hypt is 5

cos = 3/5

tan is negative in quad 2 and 4

sin is positive in quad 1 and 2

so because tan is negative and sine is positive the cosine is negative

-3/5

6 0
2 years ago
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