Answer:
The bigger avocado will be a better deal if the ratio of the sizes of the bigger one to the smaller one is less than the ratio of the prices of the bigger one to the smaller one.
Step-by-step explanation:
Given that two sizea of avocados are being sold, since the regular size is being sold for $0.84 each, let the price for the bigger avocado be $x.
Then note the following:
1. How bigger than the smaller avocado is the bigger one?
This would determine if the price for the bigger one is a bargain, or a mistake.
If for instance, the bigger avocado is double the size of the smaller one, then for any price, $x less that $1.68 (twice of $0.84), it is a bargain.
The bigger avocado will be a better deal if the ratio of the sizes bigger one to the smaller one is less than the ratio of the prices of the bigger one to the smaller one.
I assume you mean x squared in the first equation
Because both are equal to y, they are equal to each other so x + 5 = x^2 +3
If we then move everything over to one side, we get x^2 - x - 2 = 0
Then factorise it to (x-2)(x+1) = 0
And solve both parts separately
x + 1 = 0
x = -1
x-2 = 0
x = 2
Sub both values into the simplest equation in this case y=x+5
to get y = 4 and y = 7
25(1)=25
25+0=25
Those are the only ones that are true
First Division, next Addition and Subtraction (left-to-right)
4 + 8 : 2 - 1 = 4 + 4 - 1 = 8 - 1 = 7
<h3>Answer: b. 7</h3>
