Please answer both zoom close so you can see the picture.

Which of the following represents this function written in intercept form?

rodikova [14]

The answer is

C. - (x + 3)(x - 4)

because if you solve this....

- (x + 3)(x - 4)
(-x - 3)(x - 4)
-x^2 +4x - 3x + 12

-x^2 + x + 12

6 0

2 years ago

Use Euler's formula to write 3+3i^3 in exponential form.

Alex_Xolod [135]

21−=2(2−)=2cos(−1)+2 sin(−1)

−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2

Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.

complex-numbers

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edited Mar 6 '17 at 4:38

Richard Ambler

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asked Mar 6 '17 at 3:34

14wml

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1 Answer

1

No. It is not true that =cos()+sin(). Notice that

1=1≠cos()+sin(),

for example consider this at =0.

As a hint for figuring this out, notice that

+=ln(+)

then recall your rules for logarithms to get this to the form (+)ln().

8 0

3 years ago

You use a 40% off coupon followed by a 30% off coupon. is that

Natalija [7]

Answer:

Yes since 40+30=70 so it would be the same

Step-by-step explanation:

6 0

3 years ago

Four accounting majors, two economics majors, and three marketing majors have interviewed for five different positions with a la

Slav-nsk [51]

Answer:

Option c

Step-by-step explanation:

From the question we are told that:

Four accounting majors $N_a=4$

Two economics majors $N_e=2$

Three marketing majors $N_m=3$

Total Applicants N_T=9

Generally the equation for Different ways that five of these could be hired is mathematically given by

$X_5=^9P_5$

$X_5=\frac{9!}{(9-5)!}$

$X_5=15120$

Generally the equation for Different ways that Three of these could be hired is mathematically given by

$X_3=^9P_3$

$X_3=\frac{9!}{(9-5\3)!}$

$X_3=504 ways$

Option c

5 0

3 years ago

A store manager is looking at past jewelry sales to determine what sizes of rings to keep in stock. The list shows the ring size

scoundrel [369]

Using it's concept, it is found that the variance of the data-set is of 1.15.

The mean of a data-set is the <u>sum of all observations divided by the number of observations,</u> hence:

$E(X) = \frac{9 + 7 + 6.5 + 7.5 + 7 + 8 + 5 + 6 + 7.5 + 8}{10} = 7.15$

The variance is the <u>sum of the differences square between each value and the mean, divided by the number of values</u>. Hence:

$V(X) = \frac{1}{10}[(9 - 7.15)^2 + (7 - 7.15)^2 + (6.5 - 7.15)^2 + (7.5 - 7.15)^2 + (7 - 7.15)^2 + (8 - 7.15)^2 + (5 - 7.15)^2 + (6 - 7.15)^2 + (7.5 - 7.15)^2 + (8 - 7.15)^2] = 1.15$

A similar problem is given at brainly.com/question/1527299

3 0

2 years ago