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3 years ago

If the spin rate of the CD is 580 rpm what distance is traveled by the piece of dust (in radians) in 2.9 mins

Mathematics

1 answer:

natta225 [31]3 years ago

7 0

Answer:

$d=10568.76rads$

Step-by-step explanation:

From the question we are told that:

Angular Velocity $\omega=580rpm=>60.74rads/sec$

Time $t=2.9mins=>174sec$

Generally the equation for distance d is mathematically given by

$d=\omega*t$

$d=60.74*174$

$d=10568.76rads$

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4. In a sample of 1000 people, 130 can wiggle their ears. Two unrelated people are

Elina [12.6K]

Using the hypergeometric distribution, it is found that there is a 0.7568 = 75.68% probability that neither can wiggle his or her ears.

The people are chosen from the sample without replacement, which is why the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.

In this problem:

1000 people means that $N = 1000$
130 can wiggle their ears, thus $k = 130$
Two are selected, thus $n = 2$ .

The probability that neither can wiggle his or her ears is P(X = 0), thus:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = x) = h(0,1000,2,130) = \frac{C_{130,0}C_{870,2}}{C_{1000,2}} = 0.7568$

0.7568 = 75.68% probability that neither can wiggle his or her ears.

A similar problem is given at brainly.com/question/24826394

5 0

2 years ago

Evaluate 2b^2 − 4a + 4a^2 for a = 3 and b = −8.

kipiarov [429]

(2*(-8)^2)-(4*3)+(4*3^2)

128-12+36

152

6 0

3 years ago

If cosθ=2/3 find cscθ using identities. This is in quad. 1.

laiz [17]

Step-by-step explanation:

cos θ = 2/3

$\quad \twoheadrightarrow\sf {cos \; \theta = \dfrac{Base}{Hypotenuse} } \\$

Hence, base = 2 units and hypotenuse = 3 units.

$\quad \twoheadrightarrow\sf { H^2 = B^2 + P^2} \\$

$\quad \twoheadrightarrow\sf { P^2 = H^2 - B^2} \\$

$\quad \twoheadrightarrow\sf { P^2 = (3)^2 - (2)^2} \\$

$\quad \twoheadrightarrow\sf { P^2 = 9- 4} \\$

$\quad \twoheadrightarrow\bf { P = \sqrt{5}} \\$

Now, we know that :

$\quad \twoheadrightarrow\sf {cosec \; \theta = \dfrac{Hypotenuse}{Perpendicular} } \\$

$\quad \twoheadrightarrow\bf{cosec \; \theta = \dfrac{3}{\sqrt{5}} } \\$

Therefore, the required answer is 3/√5.

4 0

2 years ago

IT COST $9 TO GO TO PETE'S POTTERY PLACE TO MAKE YOUR OWN BOWLS $3 PER BOWL. NATALIE GOES TO PETE'S POTTERY PLACE AND MAKES B BO

S_A_V [24]

C= 5(9*3b)
C= 5(9*12)
C= 5(108)
C=540

8 0

3 years ago

Which is the smallest number in this set of numbers? A. √8 B. 14/5 C. 2.28 D. 2.288

-Dominant- [34]

Answer:

Step-by-step explanation:

a = 2.828

b = 2.800

c = 2.288

d = 2.288

8 0

3 years ago

Read 2 more answers