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3 years ago

If the spin rate of the CD is 580 rpm what distance is traveled by the piece of dust (in radians) in 2.9 mins

Mathematics

1 answer:

natta225 [31]3 years ago

7 0

Answer:

$d=10568.76rads$

Step-by-step explanation:

From the question we are told that:

Angular Velocity $\omega=580rpm=>60.74rads/sec$

Time $t=2.9mins=>174sec$

Generally the equation for distance d is mathematically given by

$d=\omega*t$

$d=60.74*174$

$d=10568.76rads$

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Reason:

The given calculation is presented as follows;

1. a > 0, b > 0 given

2. a = b given

3. a·b = b²

4. a·b - a² = b² - a²

5. a·(b - a) = (b + a)·(b - a)

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8. b = 2·b

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From line 4, the result are;

4. a·b - a² = b² - a² = 0

5. a·(b - a) = (b + a)·(b - a) = 0

On line 6, both sides where divided by (b - a) = 0, which should given an infinite result

Therefore, one rule of algebra broken is dividing by zero to get a finite result

In line 7, we have;

7. 0 = b

From 6. a = b + a, and a = b, we have;

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However

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