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Natali [406]
3 years ago
11

If the spin rate of the CD is 580 rpm what distance is traveled by the piece of dust (in radians) in 2.9 mins

Mathematics
1 answer:
natta225 [31]3 years ago
7 0

Answer:

d=10568.76rads

Step-by-step explanation:

From the question we are told that:

Angular Velocity \omega=580rpm=>60.74rads/sec

Time t=2.9mins=>174sec

Generally the equation for distance d is mathematically given by

 d=\omega*t

 d=60.74*174

 d=10568.76rads

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