7. 1/4
8. 1/8
9. 1/7
Estimated
<em>Answer</em>
B) y = 3
<em>Step-by-step explanation</em>
Given the system of equations:

Isolating x from equation 1:

Substituting equation 3 into equation 2 and solving for y:

Answer:
In 3 - 5:
3 + (-5), and -5 + 3
In 5 - 3:
5 + (-3), and -3 + 5
Step-by-step explanation:
Category : 3 - 5
Values must equal -2
3 + (-5) = 3 - 5 = -2
-5 + 3 = -2
Category : 5 - 3
Values must equal 2
5 + (-3) = 5 - 3 = 2
-3 + 5 = 2
If my answer is incorrect, pls correct me!
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-Chetan K
Answer: (f·g)(x) = -5x³ - 31x² + 62x + 18
(f·g)(-1) = -70
(fog)(x) = 25x² - 130x + 155
(fog)(-1) = 310
<u>Step-by-step explanation:</u>
f(x) = x² + 8x + 2 g(x) = -5x + 9
(f·g)(x) = (x² + 8x + 2)(-5x + 9)
= -5x³ + 9x²
- 40x² + 72x
<u> - 10x + 18</u>
= -5x³ - 31x² + 62x + 18
(f·g)(-1)= -5(-1)³ - 31(-1)² + 62(-1) + 18
= -5(-1) - 31(1) - 62 + 18
= 5 - 31 - 62 + 18
= -70
****************************************************************************************
(fog)(x) = (-5x + 9)² + 8(-5x + 9) + 2
= 25x² - 90x + 81
- 40x + 72
<u> + 2</u>
= 25x² - 130x + 155
(fog)(-1) = 25(-1)² - 130(-1) + 155
= 25 + 130 + 155
= 310
<em>It wasn't clear if you wanted multiplication or composition so I solved both.</em>
What- what are the questions