The frequency of a wave becomes higher due to the object moving at a fast pace coming towards you with shorter wavelengths (depending on the speed) aka the Doppler Effect.
Hope this helps
Given Information:
Initial speed of rock = vi = 30 m/s
escape speed of the asteroid = ve = 24 m/s
Required Information:
final speed of rock = vf = ?
Answer:
vf = 18 m/s
Explanation:
As we know from the conservation of energy
KEf + Uf = KEi + Ui
Where KE is the kinetic energy and U is the potential energy
0 + 0 = ½mve² - GMm/R
When escape speed is used, KEf is zero due to vf being zero. Uf is zero because the object is very far away from mass M, therefore, the equation becomes
GMm/R = ½mve²
m cancels out
GM/R = ½ve²
GM/R = ½(24)²
GM/R = 288
KEf + Uf = KEi + Ui
½mvi² + 0 = ½vf² - GMm/R
m cancels out
½vi² = ½vf² - GM/R
Substitute the values
½(30)² = ½vf² - (288)
½vf² = 450 - 288
vf² = 2(162)
vf = √324
vf = 18 m/s
Therefore, the final speed of the rock is 18 m/s
I am 11 year old and I don't known the answer to this question
Answer:
C. Plate Tectonics
Explanation:
The theory of plate tectonics is when the lithosphere is separated into plates. These plates move over or float over the asthenosphere. The movement of these plates cause earthquakes and can interact with the volcanic activity.
A) The mass is an intrinsic property of an object: it means it depends only on the properties of the object, so it does not depend on the location of the object. Therefore, Gary's mass at 300 km above Earth's surface is equal to his mass at the Earth's surface.
b) The weight of an object is given by

where
m is the mass

is the gravitational acceleration at the location of the object, with G being the gravitational constant, M the mass of the planet and r the distance of the object from the center of the planet.
At the Earth's surface,

, so Gary's weight is

(1)
where m is Gary's mass.
Then, we must calculate the value of g at 300 km above Earth's surface. the Earth's radius is

So the distance of Gary from the Earth's center is

The Earth's mass is

, so the gravitational acceleration is

Therefore, Gary's weight at 300 km above Earth's surface is

(2)
If we compare (1) and (2), we find that Gary's weight has changed by

So, Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.