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netineya [11]
4 years ago
11

A Tesla Roadster is traveling 97 km/hr (that's about 60 mph). How long will it take it to

Physics
1 answer:
jarptica [38.1K]4 years ago
4 0

Answer:

2.5

Explanation:

Given that Tesla Roadster is traveling 97 km/hr (that's about 60 mph). 

The speed = 97 km/h

Distance = 242.5 km

We are looking for the time. That is, the period of the journey

Using the speed formula

Speed = distance/time

97 = 242.5 / time

Time = 242.5 / 97

Time = 2.5 hours

therefore the time it will take will be 2.5

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The speed of light waves is?
denpristay [2]

Answer:

299,792,458 metres per second

Explanation:

3 0
3 years ago
Suppose our experimenter repeats his experiment on a planet more massive than Earth, where the acceleration due to gravity is g
Ne4ueva [31]

Answer:

C

Explanation:

- Let acceleration due to gravity @ massive planet be a = 30 m/s^2

- Let acceleration due to gravity @ earth be g = 30 m/s^2

Solution:

- The average time taken for the ball to cover a distance h from chin to ground with acceleration a on massive planet is:

                                 t = v / a

                                 t = v / 30

- The average time taken for the ball to cover a distance h from chin to ground with acceleration g on earth is:

                                 t = v / g

                                 t = v / 9.81

- Hence, we can see the average time taken by the ball on massive planet is less than that on earth to reach back to its initial position. Hence, option C

7 0
3 years ago
An automobile having a mass of 1,000 kg is driven into a brick wall in a safety test. The bumper behaves like a spring with cons
Nady [450]

To solve this problem it is necessary to apply the concepts related to the conservation of energy, specifically the potential elastic energy against the kinetic energy of the body.

By definition this could be described as

PE = KE

\frac{1}{2}kx^2 = \frac{1}{2}mv^2

Where

k = Spring constant

x = Displacement

m = mass

v = Velocity

This point is basically telling us that all the energy in charge of compressing the spring is transformed into the energy that allows the 'impulse' seen in terms of body speed.

If we rearrange the equation to find v we have

v = \sqrt{\frac{kx^2}{m}}

Our values are given as

m = 1000kg

k = 5.75*10^6N/m

x = 3.12*10^{-2}m

Replacing at our equation we have then,

v = \sqrt{\frac{kx^2}{m}}

v = \sqrt{\frac{(5.75*10^6)(3.12*10^{-2})^2}{1000}}

v = 2.3658m/s

Therefore he speed of the car before impact, assuming no energy is lost in the collision with the wall is 2.37m/s

4 0
3 years ago
A solenoid inductor has an emf of 0.80 V when the current through it changes at the rate 10.0 A/s. A steady current of 0.20 A pr
barxatty [35]

Answer:

The number of turns of the inductor is 2000 turns.

Explanation:

Given;

emf of the inductor, E = 0.8 V

the rate of change of current with time, dI/dt = 10 A/s

steady current in the solenoid, I = 0.2 A

flux per turn, Ф = 8.0 μWb per

Determine the inductance of the solenoid, L

E = L(dI/dt)

L = E / (dI/dt)

L = 0.8 / (10)

L = 0.08 H

The inductance of the solenoid is given by;

L = \frac{\mu_o N^2 A}{l}

Also, the magnetic field of the solenoid is given by;

B = \frac{\mu_o NI}{l}

I is 0.2 A

B = \frac{\mu_oN(0.2)}{l} = \frac{0.2\mu_o N}{l}

\frac{B}{0.2 } = \frac{\mu_o N}{l}

L = \frac{\mu_o N^2 A}{l} \\\\L = \frac{\mu_o N }{l} (NA)\\\\L = \frac{B}{0.2} (NA)\\\\L = \frac{BA}{0.2} (N)

But Ф = BA

L = \frac{\phi N}{0.2} \\\\\phi N = 0.2 L\\\\N = \frac{0.2 L}{\phi} \\\\N = \frac{0.2 *0.08}{8*10^{-6}}\\\\N = 2000 \ turns

Therefore, the number of turns of the inductor is 2000 turns.

5 0
4 years ago
A parallel-plate vacuum capacitor has 8.38 j of energy stored in it. the separation between the plates is 2.30 mm. if the separa
avanturin [10]
<h3><u>Answer;</u></h3>

= 4.19 Joules

<h3><u>Solution;</u></h3>

Energy stored in capacitor = U = 8.38  J

U =(1/2)CV^2

C =(eo)A/d

C*d=(eo)A=constant

C2d2=C1d1

C2=C1d1/d2

Initial separation between the plates =d1= 2.30mm .  

Final separation = d2 = 1.15 mm

But; Energy=U =(1/2)q^2/C  

U2C2 = U1C1

U2 =U1C1 /C2

U2 =U1d2/d1

Final energy = Uf = initial energy × d2/d1

                                = 8.38 ×1.15/2.30

                                = 4.19 Joules

Thus; The final energy = 4.19 Joules

6 0
4 years ago
Read 2 more answers
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