All categories

3 years ago

Like that ??? Xxxxxxxxxx

Mathematics

2 answers:

Rama09 [41]3 years ago

8 0

Answer:

yeah that would be correct

andrey2020 [161]3 years ago

3 0

Answer:

yes I belive it is like that

Step-by-step explanation:

You might be interested in

Please help me with this literal equation!

ollegr [7]

Answer:

x = $\frac{n-20}{3a}$

Step-by-step explanation:

Given

$\frac{3ax-n}{5}$ = - 4

Multiply both sides by 5

3ax - n = - 20 ( add n to both sides )

3ax = - 20 + n = n - 20

Isolate x by dividing both sides by 3a

x = $\frac{n-20}{3a}$

4 0

3 years ago

Read 2 more answers

At a football game, Ben purchased x hot dogs and y drinks. He spent a total of $30.70. The equation below describes the relation

Yuki888 [10]

So I had to reread this about 3 times before it finally clicked, I've never done a problem like this before. An ordered pair is organized like so: (x-coordinate, y-coordinate) Meaning x=4 and y=6. If x=hot dogs and y=drinks then this means that Ben purchased 4 hot dogs and 6 drinks at the game.

Hope this helps!! (:

6 0

3 years ago

Pls help A. B. C. D.

Alexandra [31]

Answer:

The answer is A so put it

3 0

3 years ago

Read 2 more answers

You are ordering a meal and have $15 to spend on. The restaurant charges 6% sales tax and you plan to leave a 15% tip. The equat

Lynna [10]

Just solve the equation, x + 0.15x + 0.06x = 15
1.21x = 15,
x = $12.39 (nearly)

4 0

3 years ago

Read 2 more answers

Find dy/dx if y =x^3+5x+2/x²-1

stiks02 [169]

Differentiate using the Quotient Rule –

$\qquad$ $\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\$

According to the given question, we have –

f(x) = x^3+5x+2
g(x) = x^2-1

Let's solve it!

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2) \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5) - ( x^3+5x+2) 2x}{(x^2-1)^2 }\\$

$\qquad$ $\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\$

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\$

$\qquad$ $\pink{\therefore \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}} = \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\$

7 0

2 years ago