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olchik [2.2K]
3 years ago
7

PLEASE HELP! 40 POINTS

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
7 0

I'd start with setting up the equations. Calling x the number of students in most popular country 1, and y in country 2.

x + y = 44740

x - y = 5672

now solve for x1 and x2. You can subtract second from first:

0 + 2y = 39068

y = 19534

so

x = 5672 + 19534 = 25206

Add a sentence to answer it in words.

asambeis [7]3 years ago
4 0

total students= 44740 divided by 2 countries= 22370 for each country. if were trying to get a difference of 5672 students, then were gonna divide that 5672 by 2 which is gonna = 2836 students. country 1= 22370 students + 2836 of country 2's students. country 2 is 22370 students - 2836 students that we gave to country 1. so now, country 1 ends up with 25206 students, country 2 end up with 19534 students. a difference of 5672.

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Answer:

0.3

Step-by-step explanation:

Given:

Number of small dogs = 18

Number of medium-sized dogs = 12

Number of large dogs = 10

To find: probability that a medium-sized dog will be chosen

Solution:

Probability refers to chances of occurrence of some event.

Probability = number of favourable outcomes/total number of outcomes

Total number of dogs = 18 + 12 + 10 = 40

Number of medium-sized dogs = 12

So,

probability that a medium-sized dog will be chosen = Number of medium-sized dogs/Total number of dogs = \frac{12}{40}=0.3

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3 years ago
A bag contains 4 white,5 blacks and 2 blue balls. 3 balls are drawn one after the other without replacement from the bag .what i
Doss [256]

Answer:

24/99

Step-by-step explanation:

From the question given above, the following data were obtained:

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

Probability that they are of different color =?

Next, we shall determine the total number of balls in the bag. This can be obtained as follow:

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

TOTAL = 4 + 5 + 2 = 11 balls

Next, we shall determine the possible outcome of draw. This can be obtained as follow.

The possible outcome could be:

WBLB or WBBL or BBLW or BWBL or BLBW or BLWB

Next we shall determine the probability of each of outcomes.

Since the ball is drawn without replacement, it means the total number of ball will reduce after each draw.

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

TOTAL = 11

P(WBLB) = 4/11 × 2/10 × 5/9 = 40/990

P(WBLB) = 4/99

P(WBBL) = 4/11 × 5/10 × 2/9 = 40/990

P(WBBL) = 4/99

P(BBLW) = 5/11 × 2/10 × 4/9 = 40/990

P(BBLW) = 4/99

P(BWBL) = 5/11 × 4/10 × 2/9 = 40/990

P(BWBL) = 4/99

P(BLBW) = 2/11 × 5/10 × 4/9 = 40/990

P(BLBW) = 4/99

P(BLWB) = 2/11 × 4/10 × 5/9 = 40/990

P(BLWB) = 4/99

Finally, we shall determine the probability that they are of different color. This can be obtained as follow:

P(WBLB) = 4/99

P(WBBL) = 4/99

P(BBLW) = 4/99

P(BWBL) = 4/99

P(BLBW) = 4/99

P(BLWB) = 4/99

Probability that they are of different color =?

Probability that they are of different color = P(WBLB) + P(WBBL) + P(BBLW) + P(BWBL) + P(BLBW) + P(BLWB)

= 4/99 + 4/99 + 4/99 + 4/99 + 4/99 + 4/99

= (4 + 4 + 4 + 4 + 4 + 4)/99

= 24/99

Thus, the probability that they are of different color is 24/99

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14α - (2a + 9) = 3 (12a - 18)
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Answer:

a = 2 5/8

Step-by-step explanation:

14a - (2a + 9) = 3 (12a - 18)

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12a + 9 = 36a - 54

12a - 36a = -54 - 9

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a = -63/-24

a = 21/8

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1 Polygon H is a scaled copy of Polygon G using a scale factor of 1/4. Polygon H's area is what fraction of Polygon G's area?
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posledela

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So in order to get all the fractions to have a common denominator, we need to multiply \dfrac k{k-2} by \dfrac{k-6}{k-6}, and \dfrac1{k-6} by \dfrac{k-2}{k-2}:

\dfrac k{k-2}\cdot\dfrac{k-6}{k-6}=\dfrac{k(k-6)}{(k-2)(k-6)}=\dfrac{k^2-6k}{k^2-8k+12}

\dfrac1{k-6}\cdot\dfrac{k-2}{k-2}=\dfrac{k-2}{(k-2)(k-6)}=\dfrac{k-2}{k^2-8k+12}

Now,

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0=k^2-5k-6

We can factorize the right side:

0=(k-6)(k+1)

which tells us that k=6 and k=-1 are solutions.

4 0
3 years ago
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