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3 years ago

What are prime factors of 1000?

Mathematics

1 answer:

Ede4ka [16]3 years ago

4 0

Answer:

1,2,4,5,8,10,20,25,40,50,10,125,200,250,500,1000

Step-by-step explanation:

prime factorization is

1000=2*2*2*5*5*5

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Use the rules of equations and inverse operations to solve the equation. In your final answer, include all of your work.

Sphinxa [80]

Answer:

$x= +2\sqrt{5} or -2\sqrt{5}$

Step-by-step explanation:

for the given equation,

$4 - x^{2} = -16$

using rules of equation and inverse operations as isolating x on one side of equation,

interchanging sides of equation we get,

$x^{2} =20$

$x= +\sqrt{20} or x= -\sqrt{20}$

$x= +2\sqrt{5} or x= -2\sqrt{5}$

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4 years ago

(-2,-1) (1,-1) find the distance between two points

Daniel [21]

Answer:

Step-by-step explanation:

$\bold{METHOD\ 1:}\\\\\text{Use the formula:}\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\\text{Substitute the coordinates of the give points:}\\\\d=\sqrt{(1-(-2))^2+(-1-(-1))^2}=\sqrt{(1+2)^2+(-1+1)^2}\\\\=\sqrt{3^2+0^2}=\sqrt9=3$

$\bold{METHOD\ 2:}\\\\\text{We can see that the second coordinates of the points (ordinate) are the same.}\\\text{Therefore, the distance between these points is equal to the distance}\\\text{ between the first coordinates (abscissa).}\\\\d=|1-(-2)|=|1+2|=|3|=3$

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4 years ago

The number of permutations of n elements taken r at a time is given by the formula ________.

kondor19780726 [428]

Answer:

$P(n,r) = \dfrac{n!}{(n-r)!}$

Step-by-step explanation:

We have to fill the blank.

The number of permutations of n elements taken r at a time is given by the formula:

$P(n,r) =^nP_r = \dfrac{n!}{(n-r)!}$

Permutation is an arrangement of subsets of a larger set in regard with order of the arrangement.

where n is the the larger set and we have to choose r items from n such that there is no repetition.

In permutation, order is important.

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4 years ago

The point (-√2/2,√2/2) is the point at which the terminal ray of angle theta intersects the unit circle. what are the cosine and

Helga [31]

since that is the terminal point, then

$\bf \left( \stackrel{\stackrel{x}{cosine}}{-\cfrac{\sqrt{2}}{2}}~~,~~\stackrel{\stackrel{y}{sine}}{\cfrac{\sqrt{2}}{2}} \right)\qquad \qquad cos(\theta )=-\cfrac{\sqrt{2}}{2} \\\\\\ cot(\theta )=\cfrac{\stackrel{cosine}{-\frac{\sqrt{2}}{2}}}{\stackrel{sine}{\frac{\sqrt{2}}{2}}}\implies -\cfrac{\sqrt{2}}{2}\cdot \cfrac{2}{\sqrt{2}}\implies -1$

4 0

3 years ago

Read 2 more answers

The length is 3 inches more than the width period the width is 2 inches more than the height. The volume is 120 in.³. What is th

Debora [2.8K]

Answer:

the dimension of the box is : 8 by 5 by 3

Length = 8

Width = 5

Height = 3

Step-by-step explanation:

Let x,y and z represent the length, width and height of the box.

Given;

The length is 3 inches more than the width

x = y+3 .......1

the width is 2 inches more than the height

y = z + 2

z = y-2 .........2

Volume = length×width×height = xyz = 120 in^3

xyz = 120 ........3

Substituting equation 1 and 2 into 3

(y+3)×y ×(y-2) = 120

y(y^2+y-6) = 120

y^3 + y^2 - 6y - 120 = 0

Solving the polynomial equation we have;

y = 5

From equation 1;

x = y+3 = 5+3

x = 8

From equation 2;

z = y-2 = 5-2

z = 3

Therefore, the dimension of the box is

8 by 5 by 3

Length = 8

Width = 5

Height = 3

4 0

3 years ago