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kvasek [131]
3 years ago
9

PLEASE SOMEONE HELP A LOT OF POINTS!!

Mathematics
2 answers:
Tresset [83]3 years ago
4 0

Answer:

-5 or -3

Step-by-step explanation:

correct me if im wrong

PLEASE GIVE ME BRAINLEST I WORK HARD

hram777 [196]3 years ago
4 0

Answer:

-3

Plzzzzz give me Brainliest!!!!!

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Stuart pays back two student loans over a 4-yr period. One loan charges the equivalent of 3% simple interest and the other charg
Ugo [173]

Answer:

The first loan L1 = $20,000

This is the loan with 3% simple interest

The second loan L2 = $4,000

This is the loan with 5.5% simple interest

Step-by-step explanation:

L1 + L2 = $24,000 ...(1)

4(3% of L1) + 4(5.5% of L2) = $3,280 ...(2)

Where the first term in equation (2) represents the total interest paid on loan 1 after 4 years

The second term represents total interest accruing to loan 2 after 4 years

From equation (1), we single out L1

L1 = 24,000 - L2

Substitute this value for L1 in equation (2)

288,000 + 10L2 = 328,000

L2 = $4,000

L1 = $24,000 - $4,000 = $20,000

5 0
3 years ago
Read 2 more answers
What is the answer
Klio2033 [76]

Answer:

9

Step-by-step explanation:

Since 12 divided by 4 is 3, that is the constant. So 3 times 3 is 9

6 0
2 years ago
Write and solve a system of equations to determine how many tickets were sold before and at the music festival. PLEASE HELPPP
strojnjashka [21]

b = number of tickets sold before

a = number of tickets sold after

cost of a ticket = number of tickets times cost per ticket

before cost = 39.95b

after cost = 54.95a

total cost = 925000

39.95b + 54.95a = 925000

total number tickets = 20000

b + a = 20000

we have

39.95b + 54.95a = 925000

b + a = 20000

multiply second equation by -39.95 and add to first equation

39.95b + 54.95a = 925000

-39.95b-39.95a = -799000 +

0b+15a = 126000

15a = 126000

divide bot sides by 15

a = 8400

sub back

b + a = 20000

b+8400 = 20000

minus 8400 both sides

b = 11600

11,600 tickets sold before

8400 tickets sold after

3 0
3 years ago
Consider the binomial (u^2 − v^3)^6.
Ad libitum [116K]

Answer:

The answer to your question is:

Step-by-step explanation:

(u² - v³)⁶ = u¹² - 6(u²)⁵(v³) + 15(u²)⁴(v³)² - 20(u²)³(v³)³ + 15(u²)²(v³)⁴ - 6(u²)(v³)⁵ +

                (v³)⁶

         

             = u¹² - 6u¹⁰v³ + 15u⁸v⁶ - 20u⁶v⁹ + 15u⁴v¹² - 6u²v¹⁵ + v¹⁸

a.- Find the term that contains v⁶ = 15u⁸v⁶

b.- Find the term that contains u⁶ = - 20u⁶v⁹

c.- Find the fifth term = 15u⁴v¹²

4 0
3 years ago
A semicircle is inscribed in an isosceles triangle with base 16 and height 15 so that the
ira [324]

Answer:

  7 1/17

Step-by-step explanation:

A figure can be helpful.

The inscribed semicircle has its center at the midpoint of th base. It is tangent to the side of the isosceles triangle, so a radius makes a 90° angle there.

The long side of the isosceles triangle can be found from the Pythagorean theorem to be ...

  BC² = BD² +CD²

  BC² = 8² +15² = 289

  BC = √289 = 17

The radius mentioned (DE) creates right triangles that are similar to ∆BCD. In particular, we have ...

  (long side)/(hypotenuse) = DE/BD = CD/BC

  DE = BD·CD/BC = 8·15/17

  DE = 7 1/17 ≈ 7.059

8 0
2 years ago
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