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3 years ago

What is the equation of the line that passes through the point (3,-6) and has a slope of 4/3?

Mathematics

2 answers:

soldi70 [24.7K]3 years ago

7 0

Answer:

y=4/3x+2

Step-by-step explanation:

Anastaziya [24]3 years ago

7 0

Answer:

y=4/3x-10

Step-by-step explanation:

y=mx+c

y=4/3x+c

-6=4/3(3)+c

-6=4+c

-4 on both sides

-10=c

y=4/3x-10

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3 years ago

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zalisa [80]

Answer:

a. (x+5)^2 = 49

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Solve completely (all missing sides and all missing angles) using trig ratios or laws. Round to the nearest tenth.

hodyreva [135]

Answer:

Step-by-step explanation:

3. Use Cosine law to find the length of the unknown side (PR)

q² = p² + r² - 2prCos Q

q is the opposite side of ∠Q;

p is the opposite side of ∠P; p = 33

r is the opposite sides of ∠R ; r = 67

q² = 33² + 67² - 2* 33*67 Cos 19°

= 1089 + 4489 - 4422 * 0.95

= 1089 + 4489 - 4200.9

= 1377.1

q = √1377.1

q = 37.1

PR = 37.1

To find the angle use law of sin

$\sf \dfrac{q}{Sin \ Q} =\dfrac{p}{Sin \ P}\\\\\\\dfrac{37.1}{Sin \ 19}=\dfrac{33}{Sin \ P} \\\\\\\dfrac{37.1}{0.33}=\dfrac{33}{Sin \ P}\\\\\\37.1* Sin \ P = 33 *0.33\\\\Sin \ P =\dfrac{33*0.33}{37.1}$