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Alina [70]
3 years ago
14

Plsssss helps no other stuff

Mathematics
1 answer:
nignag [31]3 years ago
4 0
Jane has the greater median
You might be interested in
1/X+4 = 5 it is solving rational equations
finlep [7]
X=1
Subtract four so you get 1/x=1
Multiply by x
1x=1
Divide by 1
7 0
3 years ago
We suspect the overall mean monthly rent of apartments in Shadyside is higher than in Oakland, so we survey a random sample of O
Nikolay [14]

Answer:

B

Step-by-step explanation:

A. matched-pair t-test is used ot deterrmine whether two samples are different because sometihng has changed  and there are two distributions or there is effectively one distribution. In this scenario  only mean of two population is being compared and not the effect of any variable

B. two sample t-test  is used to determine whether average between two groups is significantly different or not. In this scenario, mean values of two populatinos are being compared.

C. ANOVAD is used to determine whether means of three or more statistically independent groups are significantly different or not. In this scenario, we have only two groups.

D. Chi-squaed test is used to test relationships between two variables. In this scenario, no relationship is being tested.

E. Inference of regression is used to determine how one population of x-values is dependent on another population of y-values based on the each individual sample values. In this scenario, we are not comparing individual values of two population

4 0
3 years ago
Given the sequence {-1, 3, 7, 11, ...}, find a25
Lesechka [4]

here,

a1=-1

a2=-1+4 =3

a3= 3+4=7

a4=7+4=11

using the general formula for nth term of an ap

an =  - 1 + (n - 1)d \\ here \: a =  - 1 \: and \: d = 4 \\  \\ an =  - 1(n - 1)(4) =  - 1 + 4 - 4  \\ 4n - 5 \\  \\ hence \: a25  =  \\ 4(25) - 5 = 100 - 5 = 95

Answer= a25 = 95

4 0
3 years ago
Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b
jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that  R should represent the set of all possible outcomes generated from  a bit string of length 10 .

So; as each place is fitted with either 0 or 1

\mathbf{|R|= 2^{10}}

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if  a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

\mathbf{P(E) = \dfrac{|E|}{|R|}}

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

\mathbf{{|E|}=1 }   ; \mathbf{|R|= 2^{10}}

\mathbf{P(E) = \dfrac{1}{2^{10}}}

4 0
3 years ago
I Need help!!!!!!!!!!!!!!!
astra-53 [7]
Answer:
The answer is B.

Explanation:
Because -1 is bigger than -13.
5 0
3 years ago
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