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Alex787 [66]
3 years ago
7

I require some assistance with this graphing question, please.

Mathematics
2 answers:
Allisa [31]3 years ago
8 0

Answer:

y-int = 5

roots: sqrt(5)-3 or -3 - sqrt(5)

TP @ (-3,5)

Step-by-step explanation:

y intercept = 5 (when x = 0)

Roots:

When y = 0

5 - (x + 3)^2 = 0

(x+3)^2 = 5

Square both sides:

x + 3 = Sqrt[5] or x + 3 = - Sqrt[5]

x = Sqrt[5] - 3 or x= - 3 - Sqrt[5]

Turning point (Critical Point):

dy/dx (5-(x+3)^2) = - 2 (x+3)

Solve -2 (x+3) = 0

x = - 3

y = 5

Max point at (-3,5)

Hoochie [10]3 years ago
6 0

Answer:

vertex (-3,5) and another pt (-2,4)

Step-by-step explanation:

It is in vertex form so the vertex is (-3,5)...

Now just plug in a value for x say like -2...

f(-2)=-(-2+3)^2+5

f(-2)=-(1)^2+5

f(-2)=-1+5

f(-2)=4

So another point is (-2,4)

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Given segments AB and CD intersect at E.
nata0808 [166]

The length of a segment is the distance between its endpoints.

  • \mathbf{AB = 3\sqrt{2}}
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<u>(a) Length of AB</u>

We have:

\mathbf{A = (1,2)}

\mathbf{B = (4,5)}

The length of AB is calculated using the following distance formula

\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

So, we have:

\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}

\mathbf{AB = \sqrt{18}}

Simplify

\mathbf{AB = 3\sqrt{2}}

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

Where:

\mathbf{C = (2, 4)}

\mathbf{D = (2, 1)}

So, we have:

\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}

\mathbf{CD = \sqrt{9}}

\mathbf{CD = 3}

By comparison

\mathbf{CD \ne AB}

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

\mathbf{AB = \frac 12 \times CD}

The above equation is not true, because:

\mathbf{3\sqrt 2 \ne \frac 12 \times 3}

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

\mathbf{CD = \frac 12 \times AB}

The above equation is not true, because:

\mathbf{3 \ne \frac 12 \times 3\sqrt 2}

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0
2 years ago
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