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GaryK [48]
3 years ago
13

This is pre calculus please help !Describe three ways to determine the measure of segment YZ.

Mathematics
2 answers:
Dmitry [639]3 years ago
7 0
(1) Using trigonometric ratios:
sin(30) = \frac{YZ}{50}
YZ = 25

(2) Using Pythagoras' Theorem:
cos(30) = \frac{XY}{50}
50cos(30) = XY
50^{2} - 50^{2}cos^{2}(30) = YZ^{2}
2500 - 2500cos^{2}(30) = YZ^{2}
YZ = 25

(3) Using sine rule:
\frac{50}{sin(90)} = \frac{YZ}{sin(30)}
50 = \frac{YZ}{sin(30)}
50sin(30) = YZ
YZ = 25
disa [49]3 years ago
5 0

Which did you include in your response?

Solve the equation where the sine of 30 degrees is equal to YZ/50.

Solve the equation where the tangent of 30 degrees is equal to YZ/50.

Solve 180 - (30 + 90) = 60 to find the measure of angle Z. Then use the cosine of Z to write and solve an equation.

Use the 30°-60°-90° triangle theorem to find that YZ = 50/2.

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Hiro rolls a fair pair of six-sided dice. The sample space of all possible outcomes is shown below. Let AAA be the event that th
Eva8 [605]

Step-by-step explanation:

P(A or B) = P(A) + P(B) − P(A and B)

P(A or B) = 6/36 + 5/36 − 0/36

P(A or B) = 11/36

3 0
4 years ago
How many bucketloads would it take to bucket out the world’s oceans? Write your answer in scientific notation.
kodGreya [7K]

Answer: 7\times10^{19} buckets

Step-by-step explanation:

Given:  A cubic kilometer=10^{15}cubic centimeters

The volume of  world’s oceans=1.4\times10^{9} cubic kilometers of water.

⇒ The volume of  world’s oceans=1.4\times10^{9}\times10^{15} cubic centimeters of water.

Volume of a bucket = 20,000 cubic centimeters of water.

The number of bucket-loads would it take to bucket out the world’s oceans

n=\frac{\text{volume of ocean}}{\text{volume of bucket}}=\frac{1.4\times10^{9}\times10^{15}}{20000}

\Rightarrow\ n=\frac{1.4\times10^{9+15}}{0.2\times10^5}......[a^n\times a^m=a^{m+n}]\\\Rightarrow\ n=7\times10^{24-5}.....[\frac{a^m}{a^n}=a^{m-n}]\\\Rightyarrow\ n=7\times10^{19}

hence,  7\times10^{19} bucketloads would it take to bucket out the world’s oceans.

5 0
3 years ago
James has a piece of construction paper with an area of 50 1/4 inches. It is 4 3/16 inches long. What is the width of the piece
Flura [38]

Answer:

The width of the piece of construction paper is 12 inches.

Step-by-step explanation:

The length of the construction paper=   4 3/16 in log

4\frac{3}{16} = 4 +  \frac{3}{16} = 4 + 0.1875 = 4.1875

⇒Length of the paper = 4.1875 inches

Let the width of the paper = w inches

The area of the paper = 50 1/4   sq. inches.

50\frac{1}{4} = 50 +  \frac{1}{4} = 50 + 0.25 = 50.25

⇒Area of the  paper = 50.25 sq. inches

Now, Area of the paper = LENGTH x WIDTH

or, 50.25 sq. inches  = 4.1875 inches x w

⇒ w = 50.25  / 4.1875 = 12 in

or, w = 12 in

Hence, the width of the piece of construction paper is 12 inches.

6 0
4 years ago
In the morning, Mary walked 2 1/4 miles
slamgirl [31]

Answer:

7 1/8 miles.

Step-by-step explanation:

6 0
3 years ago
Graph the inequality.<br> -6 ≤y + 2x &lt; 15
omeli [17]

Inequalities help us to compare two unequal expressions. The correct option is B.

<h3>What are inequalities?</h3>

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.


The given inequality -6 ≤y + 2x < 15 can be broken into two small inequality, as shown below.

  • -6 ≤y + 2x
  • y + 2x < 15

Now, if we plot the inequality as shown below, then the area in which both the shaded region overlap is the area of the this inequality.

Hence, the correct option is B.

Learn more about Inequality:

brainly.com/question/19491153

#SPJ1

6 0
3 years ago
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