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GaryK [48]
3 years ago
13

This is pre calculus please help !Describe three ways to determine the measure of segment YZ.

Mathematics
2 answers:
Dmitry [639]3 years ago
7 0
(1) Using trigonometric ratios:
sin(30) = \frac{YZ}{50}
YZ = 25

(2) Using Pythagoras' Theorem:
cos(30) = \frac{XY}{50}
50cos(30) = XY
50^{2} - 50^{2}cos^{2}(30) = YZ^{2}
2500 - 2500cos^{2}(30) = YZ^{2}
YZ = 25

(3) Using sine rule:
\frac{50}{sin(90)} = \frac{YZ}{sin(30)}
50 = \frac{YZ}{sin(30)}
50sin(30) = YZ
YZ = 25
disa [49]3 years ago
5 0

Which did you include in your response?

Solve the equation where the sine of 30 degrees is equal to YZ/50.

Solve the equation where the tangent of 30 degrees is equal to YZ/50.

Solve 180 - (30 + 90) = 60 to find the measure of angle Z. Then use the cosine of Z to write and solve an equation.

Use the 30°-60°-90° triangle theorem to find that YZ = 50/2.

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Alan is 15. Beth is 16 and Caleb is 17
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If there are three noncollinear points there is always one plane?
guajiro [1.7K]

Answer:

Yes I believe there is.

Step-by-step explanation:

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F(x)=3x+5/x, what is f(a-2)
grin007 [14]

Replace x with the binomial a - 2.

f(a - 2) = [3(a - 2) + 5]/(a- 2)

f(a - 2) = [3a - 6 + 5]/(a - 2)

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8 0
3 years ago
A rose garden is formed by joining a rectangle and a semicircle, as shown below. The rectangle is 31 ft long and 20 ft wide. If
forsale [732]
<h3>Answer:</h3>

133 ft

<h3>Step-by-step explanation:</h3>

Given in the question,

length of the rectangle = 31 ft

width of the rectangle= 20 ft

diameter of semicircle = 20 ft

radius of semicircle = 20/2 ft = 10 ft

<h3>Formula to use:</h3>

perimeter of rectangle + perimeter of semicircle

perimeter of rectangle = 2(l+w)

perimeter of semicircle = 1/2(2πr)

<h3>Plug values in the formula above</h3>

2(31 + 20) + 3.14(10)

133.4 ft

≈ 133 ft

8 0
3 years ago
Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. We learned about the de
attashe74 [19]

The question is incomplete. Here is the complete question.

Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.

a) Determine the arc length to the nearest tenth of an inch.

b) Explain why the following proportion would solve for the length of AC below: \frac{x}{12\pi } = \frac{130}{360}

c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.

Note: The image in the attachment shows the arc to solve this question.

Answer: a) 9.4 in

c) x = 13.6 in

Step-by-step explanation:

a) \frac{arclength}{2\pi.r } = \frac{mAB}{360}, where:

r is the radius of the circumference

mAB is the angle of the arc

arc length = \frac{mAB.2.\pi.r }{360}

arc length = \frac{90.2.3.14.6}{360}

arc length = 9.4

The arc lenght for the image is 9.4 inches.

b) An <u>arc</u> <u>length</u> is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):

\frac{x}{2.6.\pi } = \frac{130}{360}

\frac{x}{12\pi } = \frac{130}{360}

c) Resolving (b):

x = \frac{130.12.3.14}{360}

x = 13.6

The arc length for the image is 13.6 inches.

6 0
3 years ago
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