This is the concept of application of quadratic expressions. Given that the height of the ball is modeled by the equation;
h=-7.3t^2+8.25t+2.1+5
The time taken for the ball to hit the ground will be given as falls;
-7.3t^2+8.25t+7.1=0
to solve for t we use the quadratic formula;
t=[-b+/-sqrt(b^2-4ac)]/(2a)
a=-7.3, b=8.25, c=2.1
t=[-8.25+/-sqrt[8.25^2+4*7.3*7.1]/(-2*7.3)
t= -0.572
or
t=1.702
since there is not negative time we take the time taken for the ball to hit the ground will be: t=1.702 sec
Answer:
y = 
x
Step-by-step explanation:
slope-intercept form: y = mx + b
Given: slope(m) = , point (4, -3)
We already have the value of m, but we need to find the value of b. To do this, input the given values of the slope and the point into the equation:
-3 = (4) + b
Solve for b:
-3 = (4) + b
-3 = -3 + b
0 = b
The value of b is zero. We can now write the equation:
y = x + 0
y = x
The equation written in slope-intercept form is: y = x
Understand that a function<span> is a rule that assigns to each input exactly one output. The graph of a </span>function<span> is the set of ordered pairs consisting of an input and the corresponding output.</span>
