3 were called on Friday.
Then the each of the 3 called 3 others which all equals to 9, since 3*3 is 9.
Now, each of the 9 called 3 others on Sunday which altogether equals 27, since 9*3 is 27. Therefore, the answer is 27.
Every time the word each is used in a math problem, that would mean that you need to multiply something. And that's what happened here
Answer:
Divisible by 3 is the answer
Step-by-step explanation:
First get everything to have the same base of 5
25^11 - 5^19
(5^2)^11 - 5^19
5^(2*11) - 5^19
5^22 - 5^19
Now factor out the GCF 5^19 to get
5^22 - 5^19
5^(19+3) - 5^(19+0)
5^19*5^3 - 5^19*5^0
5^19(5^3 - 5^0)
5^19(125 - 1)
5^19*(124)
At this point, we factor the 124 into 31*4 to end up with this full factorization: 5^19*31*4
Therefore, 25^11 - 5^19 is equivalent to 5^19*31*4
Since 31 is a factor of the original expression, this means the original expression is divisible by 31.
I am not 100% sure but I am pretty sure the answer is (3,-1,4)
The question is asking which of the following does not have side that are parallel. So which of them have lines that would never touch if they were never ending lines.
Well, 1x5=5 and 2x5=10 so 3x5=15
