Here is some ranting.
You haven't specified programming language. And every type of loop runs only when a condition is true (that is the definition of a loop).
And here is the answer.
Well, there is [code]for[/code], [code]while[/code] and in some languages even [code]do while[/code].
Hope this helps.
Answer: Operate over existing telephone lines to carry voice, data, and video.
Explanation:
Digital subscriber line is a means of transferring high bandwidth data over a telephone line. Such data could be a voice call, graphics or video conferencing. DSL uses a user's existing land lines in a subscriber's home, allowing users to talk on a telephone line while also being connected to the Internet. In most cases, the DSL speed is a function of the distance between a user and a central station. The closer the station, the better its connectivity.
The answer to this question is the term Data Dictionary. A Data Dictionary or also known as metadata repository is a set of information that is stored which contains data, meanings, and values. The data dictionary can be used as a tool for communication between the stakeholders.
A cloud-first strategy helps this client by providing a data-centric approach that offers more speed, agility, and security. Thus, the correct option is B.
<h3>What is a Cloud-first strategy?</h3>
A cloud-first strategy may be defined as an operational strategy that allows the users to reposition all or most of their infrastructure to cloud-computing platforms.
A cloud-first strategy helps this client in numerous ways. It provides a data-centric approach that offers more speed, agility, and security to its customers or clients in a facilitated manner.
Therefore, the correct option for this question is B.
To learn more about the Cloud-first strategy, refer to the link:
brainly.com/question/24719487
#SPJ1
Answer:
Data at the following addresses will be as following:-
200 :- 34
201 :- 12
202 :- 78
203 :- 56
Explanation:
If there is 1 byte storage.
if the data is of 4 digits.Then we have to store it in 2 memory locations.
The first two digits will be stored at the higher byte address that is 201 and the last two digits will be stored at then lower byte address that is 200.
The case is same with the next data 5678.
At address 202 :- 78 will be stored and at address 203 :- 56 will be stored.
