It’s equal to 1
2x divide by 2x = 1
— —
2x divide by 2x 1
which equals to 1
ΔAOB is a right angled triangle. Therefore the Pythagorean Theorem applies in this situation.
θ is the angle from a standard position of the line OA
The length of the y component is √(1-0)2 +(-3-(-3))2] =√(12+ 02) = 1 A(-3,1) to B(-3,0) which is opposite
Then the length of the x-component is √[(-3-0)2 +(0-0)2] = √(9+0)= 3 B(-3,0) to O(0,0) which is adjacent
The length of vector OA is √[(-3-0)2 + (1-0)2] = √(9+1) = √(10) A(-3,1) to O(0,0) which is the hypotenuse of the triangle
θ = 180 - α
sinθ = sin(180-α) = opposite/hypotenuse = 1/√10
cosθ = adjacent/hypotenuse = -3/√10
tanθ = opposite/adjacent = 1/-3 = -1/3
α= arcsin(1/√10) ≈ 18
θ =180 -18 ≈162
Answer:
4
Step-by-step explanation:
duh
Answer:
50° and 130°
Step-by-step explanation:
∠1 is a chord- chord angles and is calculated as
∠1 = 0.5( arc RQ + arc ST) = 0.5(53 + 47)° = 50°
∠1 and ∠2 form a straight angle and are supplementary, hence
∠2 = 180° - 50° = 130°
We will find the inverse of the given functions:
y = x + 2 / x-2
(x-2) y = x + 2
-2y + xy = x + 2
-2y + xy = x + 2
x (y - 1) = 2 + 2y
x (y - 1) = 2 (y + 1)
x = 2 (y + 1) / (y - 1)
f (x) ^ - 1 = 2 (x + 1) / (x - 1)
The inverse is different.
f (x) = x + 1 / x-1
y = x + 1 / x-1
(x-1) y = x + 1
-y + xy = x + 1
x (y - 1) = 1 + y
x (y - 1) = (y + 1)
x = (y + 1) / (y - 1)
f (x) ^ - 1 = (x + 1) / (x - 1)
The inverse is the same.
Answer:
f (x) = x + 1 / x-1
f (x) ^ - 1 = (x + 1) / (x - 1)
f (x) = f (x) ^ - 1
