Question

Twice the sum of a number and 5 is equal to three times the difference of the number and 7. Find the number.

Answer 1

Step-by-step explanation:

Let the required number be x.

According to the given information:

$2(x + 5) = 3(x - 7) \\ \\ \therefore \: 2x + 10 = 3x - 21 \\ \\ \therefore \: 10 + 21 = 3x -2x \\ \\ \therefore \: 31 = x \\ \\ \huge \red { \boxed{\therefore \: x = 31}}$

Hence the required number is 31.