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pentagon [3]
3 years ago
11

Show the work please

Mathematics
1 answer:
Neporo4naja [7]3 years ago
3 0
False, False, True
**********
The first is false since the square root of 19 is 4 and 4/7 is not a whole number

The second is false since the square root of 40 is 6.32 which is less than 7

The last is true because the square root of 30 is 5.48 and that makes the fraction equal 3.65 which again is a whole number while 2/3 is not
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Confused! Please help and show how you did it.
natta225 [31]
The formula for the area is length times width, so for question 17, multiply those two numbers together.

If he drives 9 miles to work per day and works 5 days a week, you would need to get the total of miles per week. Then, once you do, multiply that number by 52.

7 0
3 years ago
Please help with this
Dafna1 [17]

Answer:

A

Step-by-step explanation:

● first one:

The diagonals of a rhombus are perpendicular to each others wich means that they form four right angles.

STP is one of them so this statement is true.

● second one:

If ST and PT were equal this would be a square not a rhombus.

● third one:

If SPQ was a right angle, this woukd be a square.

● fourth one:

Again if the diagonals SQ and PR were equal, this would be a square.

5 0
3 years ago
The temperature at 10 AM is 12°F. The temperature at 6 AM was -7°F. How many degrees did the temperature rise?
KatRina [158]

Answer:

19 degrees more

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Money Flow  The rate of a continuous money flow starts at $1000 and increases exponentially at 5% per year for 4 years. Find the
77julia77 [94]

Answer:

Present value =  $4,122.4

Accumulated amount = $4,742

Step-by-step explanation:

Data provided in the question:

Amount at the Start of money flow = $1,000

Increase in amount is exponentially at the rate of 5% per year

Time = 4 years

Interest rate = 3.5%  compounded continuously

Now,

Accumulated Value of the money flow = 1000e^{0.05t}

The present value of the money flow = \int\limits^4_0 {1000e^{0.05t}(e^{-0.035t})} \, dt

= 1000\int\limits^4_0 {e^{0.015t}} \, dt

= 1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4

= 1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]

= 1000 × [70.7891 - 66.6667]

= $4,122.4

Accumulated interest = e^{rt}\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t}} \, dt

= e^{0.035\times4}\times4,122.4

= $4,742

8 0
3 years ago
The average temperature of the week is 80 degrees. The first 3 days have an average of 78 and the average of the last 3 days is
Tju [1.3M]

Answer:

80

Step-by-step explanation:Solution:

step 1 Address the formula, input parameters & values.

Input parameters & values:

The given numbers are 78 & 80

step 2 Find the sum of the given two numbers.

sum = 78 + 80 = 158

step 3 Divide the sum by 2 to get the average.

average = 158/2

= 79

Thus, 79 is an average of positive integers 78 and 80.

3 0
3 years ago
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