AP teachers for<span> course and exam preparation; permission </span>for<span> any other use ... 3. Question 2. Let f and g be the functions given by ( ). (. ) 2 1. </span>f x<span> x x. = − and. ( ) (. ) ..... </span>Let f be the function given by<span> ( ). ( ) </span>sin<span> 5. ,. </span>4<span>. </span>f x<span> x </span>π<span>. = + and let ( ). P x be the ...</span>
Hello there! The answer to your question is a = 4.
To solve for a in the equation -4 + 4a = 12 you want to isolate, or separate, a from all of the equation's other values.
Our first step is to add 4 to both sides so the 4 cancels out on the left side.
-4+4 + 4a = 12+4
4a = 16
Next, we divide both sides by 4 to finish isolating a.
4/4a = 16/4
a = 4
Want to verify that this is correct? Place the value we found for a (4) into the equation in place of a and if it comes out as a true statement, the answer is correct.
-4 + 4(4) = 12
-4 + 16 = 12
12 = 12
Since 12 is in fact equal to 12, i can guarantee you that i have provided you with the correct answer. I hope this helps & have a great rest of your day! :)
Answer:
do ur test by ur own understanding... xD
Step-by-step explanation:
<h3>all the natural numbers can be expressed in the form of the product of its prime factors.</h3>
Grab some paper, a pencil, and a ruler. Make a 6 by 6 square
In order to have infinitely many solutions with linear equations/functions, the two equations have to be the same;
In accordance, we can say:
(2p + 7q)x = 4x [1]
(p + 8q)y = 5y [2]
2q - p + 1 = 2 [3]
All we have to do is choose two equations and solve them simultaneously (The simplest ones for what I'm doing and hence the ones I'm going to use are [3] and [2]):
Rearrange in terms of p:
p + 8q = 5 [2]
p = 5 - 8q [2]
p + 2 = 2q + 1 [3]
p = 2q - 1 [3]
Now equate rearranged [2] and [3] and solve for q:
5 - 8q = 2q - 1
10q = 6
q = 6/10 = 3/5 = 0.6
Now, substitute q-value into rearranges equations [2] or [3] to get p:
p = 2(3/5) - 1
p = 6/5 - 1
p = 1/5 = 0.2