All categories

3 years ago

→ PLEASE HELP ME !!! [99 POINTS] ←

Mathematics

2 answers:

Veronika [31]3 years ago

3 0

The answer is D. The number of AP tests increases as GPA increases.

steposvetlana [31]3 years ago

3 0

Hello!

I believe the answer is D) The number of AP tests increases as GPA increases.

I hope it helps!

You might be interested in

Simplify 4.2^-3 x 5.1^2 x 4.2^4 x 5.1^3

Stolb23 [73]

Answer:

14491.060542

Step-by-step explanation:

5 0

2 years ago

Find the perimeter or cm

kicyunya [14]

Answer:

The perimeter is 22.

Step-by-step explanation:

The perimeter formula (it sometimes varies) is 2(b+h)

b being base (in this example, 6)

h being height (in this example, 5)

So now, with substitution, we are left with:

2(6+5)

Which simplifies down to:

2(11)

8 0

3 years ago

(MULTIPLE CHOICE QUESTION)

Dmitrij [34]

Answer:

I believe the last is does help while the rest don't help.

Step-by-step explanation:

The first only marks O and M

The second uses O and M and only finds 2 unrelated points.

The third uses O and M to find the other 3 points

6 0

3 years ago

Read 2 more answers

The function f(x) = 1.50x – 30 gives the amount of money Amelia has to spend each week for x school lunches, after taking money

Naya [18.7K]

To find the inverse, switch the x and y, and then solve for y (f(x) is the same as y)

So we get:
x=1.50y-30 (add 30 to both sides)
x+30=1.50y (divide both sides by 1.5)
x/1.5+30/1.5=y
y=x/1.5+20

Hope this helps

7 0

2 years ago

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

3 years ago