Answer:
2 : 3
Step-by-step explanation:
4 : 6
Divide each by 2
2 : 3
The normal vector to the plane <em>x</em> + 3<em>y</em> + <em>z</em> = 5 is <em>n</em> = (1, 3, 1). The line we want is parallel to this normal vector.
Scale this normal vector by any real number <em>t</em> to get the equation of the line through the point (1, 3, 1) and the origin, then translate it by the vector (1, 0, 6) to get the equation of the line we want:
(1, 0, 6) + (1, 3, 1)<em>t</em> = (1 + <em>t</em>, 3<em>t</em>, 6 + <em>t</em>)
This is the vector equation; getting the parametric form is just a matter of delineating
<em>x</em>(<em>t</em>) = 1 + <em>t</em>
<em>y</em>(<em>t</em>) = 3<em>t</em>
<em>z</em>(<em>t</em>) = 6 + <em>t</em>
Answer:
Step-by-step explanation:
4x - 3y = 1
x + 3y = 0
Req To Solve With Elimination:
Make Them Equal:
-> 4x - 3y = 1
-> 4x + 4 . 3y = 0
Simplify:
-> 4x - 3y = 1
-> 4x + 12y = 0
-> 4x - 4x - 3y - 12y = 1
-> -3y - 12y = 1
-> -15y = 1
->
-> 
-> 
->
<em><u>Please Mark As Brainliest</u></em>
Answer:
1 solution
Key:
Assume <em>x</em> is the the range x > 0 ≥ 1, in other words, assume <em>x</em> is equal to 1.
Step-by-step explanation:
The angle of elevation<span> of an object as seen by an observer is the </span>angle<span> between the horizontal and the line from the object to the observer's eye (the line of sight). since you did give the horizontal distance between amy and the hoop, so let us represent it as x.
so the angle of elevation = tan^-1 ( (8 - 5.9) / x)
angle elevation = tan^-1 ( 2.1 / x )</span>
