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photoshop1234 [79]
2 years ago
13

A function f() is graphed on the coordinate plane.

Mathematics
1 answer:
Mkey [24]2 years ago
7 0

Answer:

i dont know but some one will help freeee points

Step-by-step explanation:

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Photo attached please help
netineya [11]

Answer:

hope it will be helpful☺️

Step-by-step explanation:

log 2 + log 2^3

2. 2

log 2 + 3 log 2

2. 2

<h3>but we know that log 2 = 1</h3><h3> 2</h3><h3>1+3= 4 </h3>

8 0
3 years ago
Identify the vertex of the quadratic function in standard form y=2x^2 -16x+31
lapo4ka [179]

Answer:

(4,1)

Step-by-step explanation:

The vertex of the quadratic can be found using -b/2a. The vertex is the point (-b/2a, f(-b/2a)).

To find the x coordinate of the quadratic, define its a,b, and c. The quadratic has a = 2, b=-16, and c=31. Then -b/2a is -(-16)/2(2) = 16/4 = 4.

To find the y-coordinate, input the x=4 and solve for y.

y=2(4)^2-16(4)+31\\y=2(16)-64+31\\y=32-64+31\\y=1

The vertex is (4,1).

8 0
3 years ago
I need help it is I ready solve inequality’s level g
AfilCa [17]

Answer:

y≤−6. Everthing more or equal to -6 should be shaded. So like fro-6 to -10

Step-by-step explanation:

Multiply each term in 12y≤−3 by 2 to eliminate the fractions.

8 0
3 years ago
Factor completely. 2x^2y+12xy+18y
Kryger [21]
2x^2y+12xy+18y 
take 2y as a common factor 
= 2y*(x^2 +6x+9)
= 2y*(x+3)*(x+3)
= 2y*(x+3)^2
6 0
3 years ago
What is the graph of the equation? y=-x^2+2x+3
daser333 [38]

Answer:

The graph is a parabola

3 0
4 years ago
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