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miv72 [106K]
2 years ago
7

Geraniums are $2.95 each. How much will 5 plants cost? (include 7% sales tax.)

Mathematics
1 answer:
Vilka [71]2 years ago
4 0
2.95x5=14.75 7% of 14.75=1.0325 14.75+1.0325=15.7825 or just $15.78
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The breaking strength of a cable is assumed to be lognormally distributed with a mean of 75 and standard deviation of 20. • If t
son4ous [18]

Answer:

If the load of magnitude 50 is hung from the cable, determine the probability of failure of the cable?

There is a 10.56% probability of failure of the cable.

If the load can take values 30, 50, and 70 with probabilities 0.2, 0.35, and 0.45 respectively, determine the probability of failure of the cable?

There is a 15.87% probability of failure of the cable.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The breaking strength of a cable is assumed to be lognormally distributed with a mean of 75 and standard deviation of 20. This means that \mu = 75, \sigma = 20.

If the load of magnitude 50 is hung from the cable, determine the probability of failure of the cable?

This is the pvalue of Z when X = 50.

Z = \frac{X - \mu}{\sigma}

Z = \frac{50 - 75}{20}

Z = -1.25

Z = -1.25 has a pvalue of 0.1056.

There is a 10.56% probability of failure of the cable.

If the load can take values 30, 50, and 70 with probabilities 0.2, 0.35, and 0.45 respectively, determine the probability of failure of the cable?

Now we have that

X = 0.2(30) + 0.35(50) + 0.45(70) = 55

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 75}{20}

Z = -1

Z = -1 has a pvalue of 0.1587.

There is a 15.87% probability of failure of the cable.

3 0
3 years ago
Joyce saved $120 on an item that was $75 off. What was the original price
vaieri [72.5K]

The original price of the item will be $ 480.When there is 75% off on the original price.

<h3>What is the percentage?</h3>

The quantity of anything is stated as though it were a fraction of a hundred. A fraction of 100 can be used to express the ratio.

The right question is

"Joyce saved $120 on an item that was 75 %  off. What was the original price?"

Given data;

% off = 75

Amount saved $120

Let the original price of the item is x

75 % of x + $120 = x

0.75x+ 120 =x

0.25 x =120

x=120/0.25

x=480

Hence, the original price of the item will be $ 480.

To learn more about percentages, refer to:

brainly.com/question/13450942

#SPJ1

5 0
1 year ago
A plane flew at a constant speed and traveled 762762762 miles in 555 hours.
ivann1987 [24]

Answer:

457657657.2

Step-by-step explanation:

(762762762/5)*3=457657657.2 miles

7 0
3 years ago
What is |–12|?<br><br> Can you help me please?
IrinaVladis [17]
The answer would be 12!!
5 0
3 years ago
Read 2 more answers
Triangle ABC has been dilated to form triangle A'B'C'. If sides AB and A'B' are proportional, what is the least amount of additi
Ede4ka [16]
When considering similar triangles, we need congruent angles and proportional sides.

Hence
"Angles B and B' are congruent, and angles C and C' are congruent." is sufficient to prove similarity of two triangles.

"Segments AC and A'C' are congruent, and segments BC and B'C' are congruent." does not prove anything because we know nothing about the angles.

"Angle C=C', angle B=B', and segments BC and B'C' are congruent." would prove ABC is congruent to A'B'C' if and only if AB is congruent to A'B' (not just proportional).

"<span>Segment BC=B'C', segment AC=A'C', and angles B and B' are congruent</span>" is not sufficient to prove similarity nor congruence because SSA is not generally sufficient.

To conclude, the first option is sufficient to prove similarity (AAA)

3 0
3 years ago
Read 2 more answers
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