Find m∠ABD and m∠CBD given m∠ABC = 111∘.
2 answers:
Answer:
m∠ABD = 88º
m∠CBD = 23º
Step-by-step explanation:
(-10x + 58) + (6x + 41) = 111
Combine like terms
-4x + 99 = 111
Subtract 99 from both sides
-4x = 12
Divide both sides by -4
x = -3
------------------------
m∠ABD = -10x + 58
m∠ABD = -10(-3) + 58
m∠ABD = = 30 + 58
m∠ABD = 88º
m∠CBD = 6x + 41
m∠CBD = 6(-3) + 41
m∠CBD = -18 + 41
m∠CBD = 23º
Answer:
88, 23
Step-by-step explanation:
<ABD + <DBC = <ABC
(-10x + 58) + (6x + 41) = 111
-10x + 58 + 6x + 41 = 111
99 - 4x = 111
-4x = 111-99
-4x = 12
x = 12/-4
x = -3
m∠ABD = -10x + 58
m∠ABD = -10(-3) + 58
m∠ABD = = 30 + 58
m∠ABD = 88º
<DBC = 6x + 41 = 6*-3 + 41 = -18 + 41 = 23
Hope it helps u
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