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2 years ago

Find m∠ABD and m∠CBD given m∠ABC = 111∘.

Mathematics

2 answers:

sineoko [7]2 years ago

7 0

Answer:

m∠ABD = 88º

m∠CBD = 23º

Step-by-step explanation:

(-10x + 58) + (6x + 41) = 111

Combine like terms

-4x + 99 = 111

Subtract 99 from both sides

-4x = 12

Divide both sides by -4

x = -3

------------------------

m∠ABD = -10x + 58

m∠ABD = -10(-3) + 58

m∠ABD = = 30 + 58

m∠ABD = 88º

m∠CBD = 6x + 41

m∠CBD = 6(-3) + 41

m∠CBD = -18 + 41

m∠CBD = 23º

lakkis [162]2 years ago

3 0

Answer:

88, 23

Step-by-step explanation:

<ABD + <DBC = <ABC

(-10x + 58) + (6x + 41) = 111

-10x + 58 + 6x + 41 = 111

99 - 4x = 111

-4x = 111-99

-4x = 12

x = 12/-4

x = -3

m∠ABD = -10x + 58

m∠ABD = -10(-3) + 58

m∠ABD = = 30 + 58

m∠ABD = 88º

<DBC = 6x + 41 = 6*-3 + 41 = -18 + 41 = 23

Hope it helps u

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