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Delicious77 [7]
3 years ago
14

15n + 24 - 4(n - 3) + 6 - 2n = 105

Mathematics
2 answers:
elena55 [62]3 years ago
7 0

Just trying to win the CONTEST BUT GOOOOD LUCK

Margaret [11]3 years ago
3 0

Step-by-step explanation:

15n +24 -4n +12 +6 -2n = 105

9n + 42 = 105

9n = 63

n = 7

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A screening test for a newly discovered disease is being evaluated for its performance as a screening test. In order to determin
Elena-2011 [213]

Answer:

- Sensitivity = 62.7 %

- specificity = 74.9 %

- positive predictive value = 45.2 %

- negative predictive value = 85.9 %

- Accuracy of the test = 71.9 %

Step-by-step explanation:

Given the data in th question;

                                 CONDITION POSITIVE    CONDITION NEGATIVE   TOTAL

TEST POSITIVE                   42                                       51                            93

TEST NEGATIVE                 25                                      152                          177

TOTAL                                  67                                     203                         270

so; A=42, B=51, C=25 and D=152

Sensitivity = [A / ( A + C) ]×100= [42 /( 42 + 25)]×100 = [42 / 67] 100=

Sensitivity = 62.7 %

specificity = [D / ( D + B) ]×100= [152 /( 152 + 51)]×100 = [152 / 203] 100=

specificity = 74.9 %

positive predictive value = [A / ( A + B) ]×100 = [42 /( 42 + 51)]×100 =[42/93] 100

positive predictive value = 45.2 %

negative predictive value =  [D / ( D + C) ]×100 = [152 /( 152 + 25)]×100 =[152/177] 100

negative predictive value = 85.9 %

Accuracy of the test = [A + D / ( A+B+C+D)] =  [42 + 152 / ( 42+51+25+152)]

= [ 194 / 270 ]

Accuracy of the test = 71.9 %

3 0
3 years ago
Randomly split the messages into a training set D1 (80% of messages) and a testing set D2 (20% of messages). Calculate the testi
Blizzard [7]

Answer:

In the step-by-step

Step-by-step explanation:

This is the code i created using the R software and the packages "caret" and "e0171".

The script was supposed to work in all general cases.

library(caret)

library(e1071)

# Categorical vector

spam <- c("spam","not_spam")

spam_vec <- sample(spam,60, replace = T)

# Supposing two independent variables so that the kappa will be close to 0.

x1 <- rnorm(60)

x2 <- rnorm(60)

# Creating the dataset

data1 <- cbind(spam_vec,x1,x2)

data1 <- as.data.frame(data1)

names(data1) <- make.names(c("spamvec","x","y"))

# Creating the partition

index <- createDataPartition(data1$spamvec,

                            p=0.8, list=FALSE)

training_data <- data1[index,]

testing_data <- data1[-index,]

fitControl <- trainControl(method = "cv",

                         number = 5,

                         savePred = TRUE,

                         classProb = TRUE)

tune.grid <- expand.grid(C = seq(0, 10, .1))

# Scaling the predictors

preProcess_cs <- preProcess(training_data[, -1],

                                 method = c("center", "scale"))

spam_training_cs      <- predict(preProcess_cs, training_data)

spam_testing_cs       <- predict(preProcess_cs, testing_data)

# Training a Naive Bayes to predict binary outcome

Naive_Bayes_Model=naiveBayes(spamvec ~.,

                            data=spam_training_cs,

                            tuneGrid = tune.grid,

                            trControl = fitControl)

# Confusion matrix

prediction <- predict(Naive_Bayes_Model, spam_testing_cs)

confusionMatrix(prediction, spam_testing_cs$spamvec, positive = "spam")

confM <- confusionMatrix(prediction, spam_testing_cs$spamvec, positive = "spam")

accuracy <- confM$overall[1]

accuracy

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3 years ago
Work out 4.52 times by 36
Mademuasel [1]

Answer:

162.72

Step-by-step explanation:

36x4=144

36x.5=18

36x.02=.72

<u>144+18+.72=162.72</u>

6 0
4 years ago
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Find the vector represented by the directed line segment with initial point A(1, −4, 1) and terminal point B(−2, 5, 4). SOLUTION
frozen [14]

Answer:

-3i +9j+3k

Step-by-step explanation:

Given that the vector is represented by the directed line segment with initial point A(1, −4, 1) and terminal point B(−2, 5, 4).

Position vector of A with respect to origin = (1, −4, 1)

position vector of B with respect to origin = (-2,5,4)

AB vector = OB-OA

= (-2-1, 5-(-4),4-1)

= (-3, 9, 3)

Line segment AB is (-3,9,3) or

-3i +9j+3k

Initial point is A and final point is B

4 0
4 years ago
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