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harkovskaia [24]
3 years ago
15

Help me please this is due today

Mathematics
2 answers:
marshall27 [118]3 years ago
8 0

Answer:

it is D.

Step-by-step explanation:

I wish it helps you

kvasek [131]3 years ago
3 0

Answer:

I think its D

Step-by-step explanation:

cuase the fruits are cheap and it's the lowest

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Please help me with this will give BRAINLIST to best answer
In-s [12.5K]

Answer:

\frac{3}{b^{0}b^{4}  }

Step-by-step explanation:

Move b^{-4} to the denominator in \frac{3b^{-4} }{b^{0} }

using the negative exponent rule b^{-n} =\frac{1}{b^{n} }

3 0
3 years ago
Plz answer I will give brainlest tag
bogdanovich [222]

Answer:

135/8

Or

16.875

Step-by-step explanation:

(3²-2²)(⅔)^-3

(9-4)(3/2)³

5(27/8)

135/8

16.875

8 0
3 years ago
A line passes through the points (2, –2) and (–6, 2). The point (a, –4) is also on the line. What is the value of a?
natka813 [3]

Answer: a = 6

Step-by-step explanation:

The slope of the line is -1/2 so if y = -4, x = 6. In your case, x is a.

Hope this helps!

4 0
3 years ago
A manufacturer produces a large number of toasters. From past experience, the manufacturer knows that approximately 1% are defec
evablogger [386]

Answer:

The probability is 0.9106

Step-by-step explanation:

The variable that says the number of defective toasters follows a binomial distribution, where we have n identical and independent events (50 toasters) with a probability p of success (1% are defective) and a probability 1-p of fail (99% are not defective). So the probability that x toasters from the 50 are defective is:

P(x) = \frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x} \\P(x) = \frac{50!}{x!(50-x)!}*0.01^{x}*(1-0.01)^{50-x}

Then, the probability P that no more than one of these toasters is defective is:

P = P(0) + P(1)

So, P(0) and P(1) are calculated as:

P(0)=\frac{50!}{0!(50-0)!}*0.01^{0}*(1-0.01)^{50-0}=0.6050

P(1)=\frac{50!}{1!(50-1)!}*0.01^{1}*(1-0.01)^{50-1}=0.3056

Finally, P is equal to:

P = 0.6050 + 0.3056 = 0.9106

3 0
3 years ago
A student was marked tardy five different times in a 40 day period. What percent of the time was the student tardy?
Reptile [31]

Answer:

12.5%

Step-by-step explanation:

5/40 = .125

.125×100 = 12.5%

4 0
3 years ago
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