The area of the circle is πr², ie. 144π.
The volume of the cilinder is 12×144π = 1728π cm³.
I vote for answer A.
Given:
t1 = 3.6 h
t2 = 4.5 h
x = speed of boat
y = speed of water
Required:
a) Expression of distance traveled with moving water with 3.6h
Expression of distance traveled with moving water with 4.5h
b) Solve for y
c) Percent of boat's speed is the water current
Solution:
Working formula: distance = velocity*time
a) For travelling downstream, we get the equation
d = (x +y)*3.6
For travelling upstream, we get the equation
d = (x-y)*4.5
b) Setting the distance as equal for travelling upstream or downstream, we arrive at the equation of
(x+y)*3.6 = (x-y)*4.5
3.6x + 3.6y = 4.5x - 4.5y
8.1y =0.9x
y = x/9
c) percentage = 1/9*100% = 11.1%
<em>ANSWERS: a) d = (x+y)*36; d = (x-y)*4.5
</em> <em>b) y = x/9
</em> <em>c) 11.1%</em>
Answer:
Step-by-step explanation:
2/3 = 0.6 repeating
3/7 = 0.42857
Answer:
Step-by-step explanation:
(5x+6)(3x-2)
"foil" it out
F: 5x * 3x = 15x^2
O: 5x * -2 = -10x
I: 6*3x = 18x
L: 6 * -2 = -12
Answer:
Step-by-step explanation:
To solve this operation we need to find the common multiple of both denominators and solve for a.
Thus, the solution is 7(a -1) / (a+2)(a-5)
