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natita [175]
3 years ago
7

Consider the reaction Upper A u (upper O upper H) subscript 3 plus upper H upper I right arrow upper A U plus upper I subscript

2 plus upper H subscript 2 upper O.. Label the half-reactions as oxidation (use "O") or reduction (use "R"). 2 upper i right arrow upper I subscript 2 plus 2 e superscript minus. Upper A u superscript plus 3, plus 3 e superscript minus right arrow upper A u.
Chemistry
2 answers:
Genrish500 [490]3 years ago
5 0

Answer:

O and R

Explanation:

maksim [4K]3 years ago
3 0

Answer:

2I- ---> I2 + 2e- = O

Au+3 + 3e- ---> Au = R

Explanation:

The first loses electrons, so it is Oxidized, and the second one gains electrons, so it is Reduced. (Also I just did this and saw the answers were O and R respectively)

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Ammonia gas has a molar mass of approximately 17 grams per mole. At 290K and 1.2 atm, a sample of ammonia has a volume of 3.7 L.
jeka94

Ammonia gas will have a mass of 3.17grams.

HOW TO CALCULATE MASS:

  • The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass.

  • However, to calculate the number of moles present in the ammonia gas given in this question, we use the formula as follows:

  • PV = nRT

where;

  1. P = pressure (atm)
  2. V = volume (L)
  3. n = number of moles (mol)
  4. R = gas law constant
  5. T = temperature

n = PV ÷ RT

n = (1.2 × 3.7) ÷ (0.0821 × 290)

n = 4.44 ÷ 23.81

n = 0.186mol

  • Mass = 0.186 × 17

  • Mass of ammonia gas = 3.17g

  • Therefore, the mass of ammonia gas is 3.17grams.

Learn more at: brainly.com/question/21085277?referrer=searchResults

6 0
3 years ago
Tricky please help !!!!!!!!
Illusion [34]
A, B, and C because they all equal 5.6 cm and it’s not close to 6.
5 0
3 years ago
How much energy (in JJ) is lost when a sample of iron with a mass of 29.2 gg cools from 79.0 ∘C∘C to 27.0 ∘C∘C?
Anna35 [415]

Answer:

- 0.674 kJ.

Explanation:

The equation used to solve this problem is:

Q = mCΔT

where,

Q = amount of heat

m = mass of the substance

C = specific heat capacity

ΔT = change in temperature

= Temp.f - Temp.i

Given:

m = 29.2 g

Temp.i = 79°C

Temp.f = 27°C

Cp(iron) = 0.444 J/g.K

Q = mCΔT

ΔT = 27.0°C - 79.0°C

= -52°C

= 29.2 * 0.444 * -52

Q = - 674.17 J

= 0.674 kJ.

6 0
3 years ago
In which equation does the term "heat" represent heat of fusion?
AleksandrR [38]
Heat of Fusion is defined as the energy required to turn a liquid into a solid, or said phase changing latent heat. In this case the only choice that represents that phase change is (1). Where the heat removed to turn a liquid of a substance into it's solid form is instead added to excite the bonds and liquify it. Yet, heat of fusion (s) ->(l)
is still the same as going from liquid to solid just one is adding and the other is removing, respectively. 
5 0
4 years ago
If the temperature of an object is 335 K, how would this be expressed on the Celsius scale?
Arturiano [62]

C it the correct answer

5 0
3 years ago
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