Answer:
The value of 
is 0.02495.
Explanation:
Initial concentration of 
gas = 0.675 M
Initial concentration of 
gas = 0.973 M
Equilibrium concentration of mustard gas = 0.35 M
initially
0.675 M 0.973 M 0
At equilibrium ;
(0.675-0.35) M (0.973-2 × 0.35) M 0.35 M
The equilibrium constant is given as :
![K_c=\frac{[S(CH_2CH_2Cl)_2]}{[SCl_2][C_2H_4]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BS%28CH_2CH_2Cl%29_2%5D%7D%7B%5BSCl_2%5D%5BC_2H_4%5D%5E2%7D)
The relation between and 
are :
where,
= equilibrium constant at constant pressure = ?
= equilibrium concentration constant =14.45
R = gas constant = 0.0821 L⋅atm/(K⋅mol)
T = temperature = 20.0°C =20.0 +273.15 K=293.15 K
= change in the number of moles of gas = [(1) - (1 + 2)]=-2
Now put all the given values in the above relation, we get:
The value of is 0.02495.
Answer:Rate of reaction can be determined in terms of concentration of reactants consumed or concentration of product formed per unit time
Explanation: For the reaction below
A ===>B
The reactant is A while the product given is B.
Reaction rate = Δ[B]/Δt = -Δ[A]/Δt
The concentration of A will decrease with time while the concentration of B will increases with time.
The negative sign in -Δ[A]/Δt is to convert the expression to positive since the change will always be negative (decreases)
Answer:
2.1mol/L
Explanation:
Number of moles = 0.21 moles
Volume = 0.1L
Molarity of a substance is the number of moles of solute dissolved in a volume of solvent (L)
Molarity = number of moles / volume of solvent
Molarity = 0.21 / 0.1
Molarity = 2.1mol/L
