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Tatiana [17]
3 years ago
15

Calculate the frequency of the n = 2 line in the Lyman series of hydrogen.

Chemistry
1 answer:
sattari [20]3 years ago
5 0
Layman series describe the ultraviolet emission lines that the hydrogen atom emits when an electron is moved from a higher energy level to level 1.

For n = 2
The wavelength = 121.5 nm
velocity = wavelength * frequency
frequency = velocity / wavelength
frequency = (3 * 10^8) / (121.5 * 10^9) = 2.469 * 10^15 Hz


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MArishka [77]
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3 0
3 years ago
What chemical compound is crucial to marine life and how is it disappearing?
daser333 [38]
Nitrogen is crucial to the marine life and it is disappearing because it cannot be assimilated by most organisms in the water.
5 0
3 years ago
We gave an object with a density of 620 g/cm^3 and a volume of 75cm^3. What is the mass of this object?
Hitman42 [59]
d=\frac{m}{V} \ \ \ \Rightarrow \ \ m=dV\\\\&#10;d=620\frac{g}{cm^{3}}\\&#10;V=75cm^{3}\\\\\&#10;m=620\frac{g}{cm^{3}}*75cm^{3}=46500g
6 0
3 years ago
For the reaction at 298 K, 2NO2(g) N2O4(g) the values of ΔH° and ΔS° are -58.03 kJ and -176.6 J/K, respectively. Calculate the v
Ierofanga [76]

Answer:

\Delta G^o=-5.4032 kJ

The temperature for \Delta G^o=0[/tex is [tex]T=328.6 K

Explanation:

The three thermodinamic properties (enthalpy, entropy and Gibbs's energy) are linked in the following formula:

\Delta G^o=\Delta H^o + T*\Delta S^o

Where:

\Delta G^o is Gibbs's energy in kJ

\Delta H^o is the enthalpy in kJ

\Delta S^o is the entropy in kJ/K

T is the temperature in K

Solving:

\Delta G^o=-58.03 kJ - 298K*-0.1766 kJ/K

\Delta G^o=-5.4032 kJ

For \Delta G^o=0:

0=\Delta H^o - T*\Delta S^o

\Delta H^o= T*\Delta S^o

T=\frac{\Delta H^o}{\Delta S^o}

T=\frac{-58.03 kJ}{-0.1766 kJ/K}

T=328.6 K

3 0
3 years ago
Read 2 more answers
Choose ALL TRUE statements about calorimetry from the choices below:
Ostrovityanka [42]

Answer:

True statment

2) Styrofoam would make a good calorimeter

3) Insulating material would make a good calorimeter

Explanation:

The calorimeter is one which is insulated that is which will not absorb or let the heat to escape from it. the calorimeter is used to measure the heat change during a process so if it will allow to exchange heat with surrounding it will deviate the readings or observence.

Copper is a good conductor of heat so we cannot use it make a calorimeter.

Hence

1) Copper would make a good calorimeter : False

2) Styrofoam would make a good calorimeter: True

Styrofoam is a bad conductor or insulator so it can be and it is used for calorimeter.

3) Insulating material would make a good calorimeter : True

4) A good calorimeter should easily absorb heat : false

6 0
3 years ago
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