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Tatiana [17]
3 years ago
15

Calculate the frequency of the n = 2 line in the Lyman series of hydrogen.

Chemistry
1 answer:
sattari [20]3 years ago
5 0
Layman series describe the ultraviolet emission lines that the hydrogen atom emits when an electron is moved from a higher energy level to level 1.

For n = 2
The wavelength = 121.5 nm
velocity = wavelength * frequency
frequency = velocity / wavelength
frequency = (3 * 10^8) / (121.5 * 10^9) = 2.469 * 10^15 Hz


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Explanation:

Hello!

In this case, for the formation of methane:

C+2H_2\rightarrow CH_4

We can see there is an excess of carbon based on their stoichiometry, because the needed amount of hydrogen gas molecules would be:

molecules _{H_2}=34atomC*\frac{2molec\ H_2}{1atomC} =68molec\ H_2

Thus, the formed molecules of methane are computed below:

molec\ CH_4=22molec\ H_2 *\frac{1molec\ CH_4}{2molmolec\ H_2} \\\\molec\ CH_4=11molec\ CH_4

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atoms \ C^{left over}=34-22molec\ H_2*\frac{1atoms C}{2molec\ H_2} \\\\atoms \ C^{left over}=23 atoms C

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