Calculate the frequency of the n = 2 line in the Lyman series of hydrogen.

1 answer:

5 0

Layman series describe the ultraviolet emission lines that the hydrogen atom emits when an electron is moved from a higher energy level to level 1.

For n = 2
The wavelength = 121.5 nm
velocity = wavelength * frequency
frequency = velocity / wavelength
frequency = (3 * 10^8) / (121.5 * 10^9) = 2.469 * 10^15 Hz

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