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3 years ago

Calculate the frequency of the n = 2 line in the Lyman series of hydrogen.

1 answer:

5 0

Layman series describe the ultraviolet emission lines that the hydrogen atom emits when an electron is moved from a higher energy level to level 1.

For n = 2
The wavelength = 121.5 nm
velocity = wavelength * frequency
frequency = velocity / wavelength
frequency = (3 * 10^8) / (121.5 * 10^9) = 2.469 * 10^15 Hz

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Calculate the volume of dry co2 produced at body temperature (37 ∘c) and 0.970 atm when 25.5 g of glucose is consumed in this re

katrin2010 [14]

I believe the balanced chemical equation is:

C6H12O6 (aq) + 6O2(g) ------> 6CO2(g) + 6H2O(l)

First calculate the moles of CO2 produced:

moles CO2 = 25.5 g C6H12O6 * (1 mol C6H12O6 / 180.15 g) * (6 mol CO2 / 1 mol C6H12O6)

moles CO2 = 0.8493 mol

Using PV = nRT from the ideal gas law:

V = nRT / P

V = 0.8493 mol * 0.08205746 L atm / mol K * (37 + 273.15 K) / 0.970 atm

V = 22.28 L

6 0

3 years ago

What is the name for this molecule? a skeletal model of an 8-carbon zig zag chain. there is a double bond between the first and

yKpoI14uk [10]

The name of the compound by using the IUPAC nomenclature of organic compounds is 1 -octene. The correct option is the last option - 1-octene.

<h3>Nomenclature of Organic compounds</h3>

From the question, we are to determine the name of the given molecule.

To name the compound, we will follow the IUPAC rules.

Some of IUPAC rules are

Find the longest continuous carbon chain. Determine the root name for this parent chain.
For Alkenes (organic compounds with double bond), number the chain of carbons that includes the C=C so that the C=C has the lower position number. Change “ane” to “ene” and assign a position number to the first carbon of the C=C.

The given compound has 8 carbons and a double bond. The root name of the compound is octane.

By IUPAC rules, the compound is an Octene.

Since the double bond is between carbon-1 and carbon-2. The compound becomes 1-octene.

Hence, the name of the compound by using the IUPAC nomenclature of organic compounds is 1 -octene. The correct option is the last option - 1-octene.

Learn more on Nomenclature of Organic compounds here: brainly.com/question/26754333

The diagram for the compound is attached below.

8 0

2 years ago

Write the condensed formula from left to right, starting with (CH3)x where x is a number.

pochemuha

Complete question:

Write the condensed formula from left to right, starting with (CH3)x where x is a number.

See attached image for the structure formula of the compound

Answer:

(CH₃)₂CHC(CH₃)₃ named as 2,2,3-Trimethylbutane

Explanation:

If we number the longest chain of the carbon starting from the left, we will observe that there are four carbons in the straight chain as shown in the image.

Starting from first carbon from the left of the carbon chain, at carbon number number 2, there two alkyl group, that is two methyl (CH3 is two). Also at carbon number 3, there are three alkyl group, that is three methyl (CH3 is three).

The condensed formula will be written as;

(CH₃)₂CHC(CH₃)₃

This compound is named as 2,2,3-Trimethylbutane, an isomer of Heptane

3 0

3 years ago

Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres

yulyashka [42]

Answer: The freezing point of solution is -0.454°C

Explanation:

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

$\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}$

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

$K_f$ = molal freezing point elevation constant = 1.86°C/m

$m_{solute}$ = Given mass of solute (KCl) = 5.0 g

$M_{solute}$ = Molar mass of solute (KCl) = 74.55 g/mol

$W_{solvent}$ = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

$0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC$

Hence, the freezing point of solution is -0.454°C

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2 years ago

Why is ginger used in food preservation

Vaselesa [24]

Spices like ginger are significantly used in preservatives because they have antimicrobial properties in their chemical compounds. They also have antioxidant properties that allow food to be preserved.

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3 years ago