A - side of small map
a+6 - side of larger map
(a+6)² - area of larger map
(a+6)² = 121
(a+6)² = 11² |√(...)
a+6 = 11 |-6
a+6-6 = 11-6
<span>a = 5
</span>Answer A. <span>5 inches by 5 inches</span>
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
yes your absolutely right
Step-by-step explanation:
you just are
If your teacher taught rise over run, then for the graphs:
y=-1/2x+1
start at y intercept of 1, then down 1, right 2 all the way, same for the other side but reversed.
y= 1/3+6
start at y intercept of 6, then up 1, right 3 all the way, same for the other side but reversed.
One solution: (-6,4)
