Answer:
Hi there, are you sure you didn't forget any parenthesis or signs? I can't find the right answer in the options, the one that would end up at -0.2 in the end I can edit my answer if you tell me some additional option or info about the expression I need to show on the number line
Step-by-step explanation:
which number line shows correctly -0.8 + 0.6?
well lets write it in words minus eight tenths plus six tenths\
so minus:
you go 0.8 units to the left from 0,
then plus:
you go 0.6 units right from -0.8, getting to -0.2
since there is no exact answer like that we can rearrange the addends 0.6-0.8, now:
we go from 0 6 tenths units to the right and get to 0.6, then we go from 0.6 eight tenths unit to the left to get to -0.2
Our P = 100, r = .08, n = 1 (annually means once a year), and t = 15. Filling in accordingly, we have

. Simplifying a bit gives us

and

. Raising that number inside the parenthesis to the 15th power gives us

. Multiplying to finish means that A(t) = $317.22
Answer:
d
Step-by-step explanation:
Slope intercept form: y = mx + b
y = -x + 7
x + y = 21
x + y = 21
-x -x
y = -x + 21
y = -x + 7
y = -x + 21
Parallel lines have the same slope. Here, our slope is -1
Therefore, our final answer is d.
Hope this helps!
Complete Question
Let P (n) be the statement that a postage of n cents can be formed using just 4-cent stamps and 7-cent stamps. The parts of this exercise outline a strong induction proof that P (n) is true for n ≥ 18.
Show statements P (18), P (19), P (20), and P (21) are true, completing the basis step of the proof.
Answer:
P(18) is true
P(19) is true
P(20) is true
P(21) is true
Step-by-step explanation:
a. When n = 18
18 cents can be formed using two 7cents and one 4cents
i.e. 2 * 7 + 4 = 18
So, P(18) is true
b. When n = 19
19 cents can be formed using one 7cents and three 4cents
i.e. 1 * 7 + 3 * 4 = 19
So, P(19) is true
c. When n = 20
18 cents can be formed using five 4cents
i.e. 5 * 4 = 20
So, P(20) is true
d. When n = 21
18 cents can be formed using three 7cents
i.e. 3 * 7 = 21
So, P(21) is true