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sdas [7]
3 years ago
13

Solve the compound inequality |3x-9|≤15 and |2x-3|≥5. Give answer in interval notation.

Mathematics
1 answer:
laila [671]3 years ago
6 0

Answer:

The solution of |3x-9|≤15 is [-2;8] and the solution |2x-3|≥5 of is  (-∞,2] ∪ [8,∞)

Step-by-step explanation:

When solving absolute value inequalities, there are two cases to consider.

Case 1: The expression within the absolute value symbols is positive.

Case 2: The expression within the absolute value symbols is negative.

The solution is the intersection of the solutions of these two cases.

In other words, for any real numbers a and b,

  • if |a|> b then a>b or a<-b
  • if |a|< b then a<b or a>-b

So, being |3x-9|≤15

Solving: 3x-9 ≤ 15

3x ≤15 + 9

3x ≤24

x ≤24÷3

x≤8

or 3x-9 ≥ -15

3x ≥-15 +9

3x ≥-6

x ≥ (-6)÷3

x ≥ -2

The solution is made up of all the intervals that make the inequality true. Expressing the solution as an interval: [-2;8]

So, being |2x-3|≥5

Solving: 2x-3 ≥ 5

2x ≥ 5 + 3

2x ≥8

x ≥8÷2

x≥8

or 2x-3 ≤ -5

2x ≤-5 +3

2x ≤-2

x ≤ (-2)÷2

x ≤ -2

Expressing the solution as an interval: (-∞,2] ∪ [8,∞)

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Ne4ueva [31]

Look at the picture.

Use the Pythagorean theorem:

b^2=a^2+a^2\\\\b^2=2a^2\to b=\sqrt{2a^2}\\\\b=\sqrt{a^2}\cdot\sqrt2\\\\b=a\sqrt2

\sin\theta=\dfrac{opposite}{hypotenuse}\\\\\theta=45^o,\ opposite=a,\ hypotenuse=a\sqrt2

substitute

\sin45^o=\dfrac{a}{a\sqrt2}=\dfrac{1}{\sqrt2}\cdot\dfrac{\sqrt2}{\sqrt2}=\dfrac{\sqrt2}{2}

Answer: \sin45^o=\dfrac{\sqrt2}{2}

7 0
3 years ago
When a particular mass-spring system is started by stretching the spring 3 cm, one complete oscillation takes 4 seconds.
11Alexandr11 [23.1K]

Answer:

A. 5.16 s.

B. 5.66 s.

Step-by-step explanation:

A.

For a simple harmonic motion,

T = 2pi (sqrt * (l/g))

Given:

L1 = 3 cm

T1 = 4 s

L2 = 5 cm

T2 = ?

4 = 2pi*sqrt(3/g)

g = 7.4

At, L2,

T2 = 2pi*sqrt(5/7.4)

= 5.16 s.

B.

M1 = M1

M2 = 2*M1

For a simple harmonic motion,

T = 2pi (sqrt * (m/k))

4 = 2pi (sqrt * (M1/k))

M1/k = 0.405

Inputting the above values,

T2 = 2pi (sqrt * (2*M1/k))

= 2pi (sqrt * (2 * 0.405))

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4 0
3 years ago
Tyler baked 702 cookies he sold them in boxes of 18 after selling all of the boxes of cookies for the same amount of each he ear
jenyasd209 [6]

Keywords:

<em>Cookies, boxes, sale, profit, unit cost </em>

For this case we have to bake an amount of 702 cookies, which were distributed in boxes of 18 for sale. Selling each box at the same price earned a profit of 136.50 dollars, you want to know the unit cost of each box of cookies.

Let "x"be the number of boxes of cookies:

So, to know the number of boxes we divide 702 cookies among 18:

x = \frac {702} {18}\\x = 39

So, we have Tyler sold 39 boxes of cookies

Now, let "y" be the cost of each box of cookies, to know the unit cost or sale price of the cookie boxes, we divided 136.50 dollars among 39 boxes of cookies, then:

y = \frac {136.50} {39}\\y = 3.5

Thus, the cost of each box was 3.5 dollars.

Answer:

The cost of a box is 3.5 dollars

5 0
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Answer:

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Step-by-step explanation:

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x=15*1000/3=5000cm which would be 50m

x=7.5*1000/3=2500cm which is 25m

the actual area of the pool is 50*25=1250 m²

8 0
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