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3 years ago

7

Which number produces a rational number when multiplied by 0.5

2 answers:

ivanzaharov [21]3 years ago

5 0

10 is your answer because it is a terminating or repeating decimals

HACTEHA [7]3 years ago

3 0

Answer:

Every Rational number when multiply by 0.5 produces a rational number.

Step-by-step explanation:

Rational Number is a number that can be changed in the formation of $\frac{p}{q}$ , where p & q are real numbers and q ≠ 0.

Even a natural number can also be a rational number since it can be change into $\frac{number}{1}$

So, the every rational number when multiply by 0.5 produces a rational number. For example: 2 × 0.5 = 1 (rational number)

7 × 0.5 = 3.5 (rational number)

42.63 × 0.5 = 21.315 (rational number)

But, $\sqrt{2}\times0.5$ = irrational as it has non terminating decimal number (also $\sqrt{2}$ is irrational number)

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X=-7+21<br> 2y-6x=6<br> need help with Substitution

Reika [66]

Answer:

x = 14 y = -3x + 3

Step-by-step explanation:

3 0

3 years ago

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

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3 years ago

Which expression is equivalent to -1/2(1/4x-3/8)?

Nesterboy [21]

A is the correct answer

7 0

3 years ago

Read 2 more answers

You deposit $2000 each year into an account earning 5% interest compounded annually. How much will you have in the account in 30

Zarrin [17]

Answer:

3000

Step-by-step explanation:

8 0

2 years ago

Given z=f(x,y),x=x(u,v),y=y(u,v), with x(1,3)=2 and y(1,3)=2, calculate zu(1,3) in terms of some of the values given in the tabl

stich3 [128]

The value of zu(1,3) using the data elements represented on the table of values is q + p

<h3>How to solve the calculus expression?</h3>

The given parameters are:

z = f(x, y)

x = x(u, v)

y = y(u, v)

Where

x(1, 3) = 2 and y(1, 3) = 2

To calculate zu(1,3), we make use of:

$z_u(1,3) = f_x(x,y) * x_u(1,3) + f_y(x,y) * y_u(1,3)$

The values x(1, 3) = 2 and y(1, 3) = 2 mean that:

(x,y) = (2,2).

So, we have:

$z_u(1,3) = f_x(2,2) * x_u(1,3) + f_y(2,2) * y_u(1,3)$

From the table of values, we have:

$f_x(2,2) = q$

$x_u(1,3) = 1$

$f_y(2,2) = 1$

$y_u(1,3) = p$

So, the equation becomes

$z_u(1,3) = q * 1 + 1 * p$

Evaluate the product

$z_u(1,3) = q + p$

Hence, the value of zu(1,3) is q + p

Read more about calculus at:

brainly.com/question/5313449

#SPJ1

3 0

2 years ago