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Maru [420]
3 years ago
10

What is the name of the stress caused by a pulling gravitational force?​

Physics
2 answers:
Simora [160]3 years ago
7 0

Answer:

Weight

Weight ( ) is a force, measured in newtons ( ). Weight is caused by the pull of gravity acting on a mass, usually near the surface of a planet.

Explanation:

garik1379 [7]3 years ago
6 0

Answer:

the answer is tension :)

Explanation:

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1.The lunch lady pushes a 100 kg zombie with 300 N of force. How much is the zombie accelerated?
Molodets [167]

Answer:

1. A=3.00m/s  2.m=50kg

Explanation:

1. Use the formula a=f/m

a=300/100

a=3

2.Use the formula m=f/a

m=1000/20

m=50kg

5 0
3 years ago
This map shows coal production around the world by region. Which answer best explains the data shown in the map?
LenaWriter [7]

Answer:

a) humidity

Explanation:

asia is known for miserable humid weather

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1 year ago
Every year, new records in track and field events are recorded. Let's take an historic look back at some exciting races.
Gala2k [10]
100 meters in 9.92 seconds,
=distance/time
=100m/9.92s 
=10.0806 m/s
4 0
3 years ago
Read 2 more answers
A 1 kg pistol, initially at rest, shoots a bullet with a mass of 2.5g. After
Allisa [31]

Answer:

Use the principle of momentum

Initial momentum = final momentum

Momentum formula = Mass * Velocity

Explanation:

6 0
2 years ago
A well lagged copper calorimeter of mas 120g contains 70g of water and 10g ice both at 0°C . Dry steam at 100°C is passed in unt
Lina20 [59]

Answer:

7.6 g

Explanation:

"Well lagged" means insulated, so there's no heat transfer between the calorimeter and the surroundings.

The heat gained by the copper, water, and ice = the heat lost by the steam

Heat gained by the copper:

q = mCΔT

q = (120 g) (0.40 J/g/K) (40°C − 0°C)

q = 1920 J

Heat gained by the water:

q = mCΔT

q = (70 g) (4.2 J/g/K) (40°C − 0°C)

q = 11760 J

Heat gained by the ice:

q = mL + mCΔT

q = (10 g) (320 J/g) + (10 g) (4.2 J/g/K) (40°C − 0°C)

q = 4880 J

Heat lost by the steam:

q = mL + mCΔT

q = m (2200 J/g) + m (4.2 J/g/K) (100°C − 40°C)

q = 2452 J/g m

Plugging the values into the equation:

1920 J + 11760 J + 4880 J = 2452 J/g m

18560 J = 2452 J/g m

m = 7.6 g

7 0
3 years ago
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