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noname [10]
3 years ago
8

PLEASE HELP!!!!!!!!!!!!!! DDDD: Please answer correctly!

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
8 0

Answer:

correct answer is G!!

Step-by-step explanation:

if you break the equation apart, you get

$200 giftcard - 4 gifts each worth x dollars = and leaves her with $80.

Hope this helps! :-)

Zepler [3.9K]3 years ago
4 0
G ...... dkjfkfkskfkmfndf
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Solve using substitution.<br> y = -2<br> -7x - y = -5
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Step-by-step explanation:

- 7x - ( - 2) =  - 5 \\  - 7x + 2 =  - 5 \\  - 7x =  - 7 \\ x = 1 \\

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All machinery must be equipped with
kakasveta [241]
Hey, the answer is c :)
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Use the rational zero theorem to create a list of all possible rational zeroes of the function f(x) = 14x^7 - 4x^2 + 2
Bas_tet [7]

f(x) = 14x^7 - 4x^2 + 2

Use the rational zero theorem

In rational zero theorem, the rational zeros of the form +-p/q

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f(x) = 14x^7 - 4x^2 + 2

In our f(x), constant is 2 and leading coefficient is 14

Factors of 2  are 1, 2

Factors of 14  are 1,2, 7, 14

Rational zeros of the form +-p/q  are

+-\frac{1,2}{1,2,7,14}

Now we separate the factors

+-\frac{1}{1}, +-\frac{1}{2}, +-\frac{1}{7}, +-\frac{1}{14},+-\frac{2}{1}, +-\frac{2}{2}, +-\frac{2}{7}, +-\frac{2}{14}

+-1, +-\frac{1}{2}, +-\frac{1}{7}, +-\frac{1}{14},+-2, +-1 , +-\frac{2}{7}, +-\frac{1}{2}

We ignore the zeros that are repeating

+-1, +-2, +-\frac{1}{2}, +-\frac{1}{7}, +-\frac{1}{14}, +-\frac{2}{7}

Option A is correct


6 0
3 years ago
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Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an
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Answer:

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x^{3} cats

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Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an expression using exponents that represents the total number of kits, cats, sacks, and wives going to St .Ives.

Step-by-step explanation:

x^{1} wives

If each of the "x" wives has "x" sacks, so the number of sacks is:

x^{2} sacks

If each of the "x" wives has "x" sacks, and each sack has "x" cats, so the number of cats is:

x^{3} cats

If each of the "x" wives has "x" sacks, and each sack has "x" cats, and each cat has "x" kits, so the number of kits is:

x^{4} kits

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:)

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