Answer:
a^2 + b^2 = c^2, where c is the hypotenus and a and b are the legs
Step-by-step explanation:
Answer:
Step-by-step explanation:
T = 4c + 25....where c = # of classes and T = total cost
2 classes...so sub in 2 for c and solve for T
T = 4(2) + 25
T = 8 + 25
T = 33 <==== with 2 classes ,its $ 33
4 classes....so sub in 4 for c and solve for T
T = 4(4) + 25
T = 16 + 25
T = 41 <==== with 4 classes, its $ 41
8 classes....sub in 8 for c
T = 4(8) + 25
T = 32 + 25
T = $ 57 <==== with 8 classes, its $ 57
10 classes...sub in 10 for c
T = 4(10) + 25
T = 40 + 25
T = 65 <===== with 10 classes, its $ 65
Answer:
13 and -14 satisfy this condition
Step-by-step explanation:
Let's represent that number as x
and the square of x is x^2
So,
x + x^2 = 182
Subtract 182 from both sides
x + x^2 - 182 = 182 - 182
x + x^2 - 182 = 0
rearrange the quadratic equation
x^2 + x -182 = 0
let's use the quadratic formula
or 
a = 1, b = 1, c = -182
or 
or 
or 
or 
or 
13 or - 14
Lets check
13 + 13^2 = 13 + 169
= 182
Also,
-14 + (-14^2) = -14 + 196
= 182