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Mila [183]
2 years ago
11

3.

Mathematics
1 answer:
Aleks [24]2 years ago
3 0

Ruby studied her science test for 1/2 of an hour

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Jamal spent 1 1/2 (1.5) hours studying for his science test ruby studied for 1/3 the amount of time that Jamal studied.

Amount of time ruby studied = (1/3) * (1.5) = 1/2 of an hour

Ruby studied for 1/2 of an hour

Find out more on equation at: brainly.com/question/1214333

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Two streets bounding your triangular lot make an angle of 74∘. The lengths of the two sides of the lot on these streets are 126
ycow [4]

Answer: a) Yes, there is enough fance

b) 58.1° and 47.9°

c) The city will not approve, because 1/3 of the area is just 2220.5ft²

Step-by-step explanation:

a) using law of cosines: x is the side we do not know.

x² = 126² + 110² - 2.126.110.cos74°

x² = 20335.3

x = 142.6 ft

So 150 > 142.6, there is enough fance

b) using law of sine:

sin 74/ 142.6 = sinα/126 = sinβ/110

sin 74/ 142.6 = sinα/126

0.006741 = sinα/126

sinα = 0.849

α = sin⁻¹(0.849)

α = 58.1°

sin 74/ 142.6 = sinβ/110

sin 74/ 142.6 = sinβ/110

0.006741 = sinβ/110

sinβ = 0.741

β = sin⁻¹(0.741)

β = 47.9°

Checking: 74+58.1+47.9 = 180° ok

c) Using Heron A² = p(p-a)(p-b)(p-c)

p = a+b+c/2

p=126+110+142.6/2

p=189.3

A² = 189.3(189.3-126)(189.3-110)(189.3-142.6)

A = 6661.5 ft²

1/3 A = 2220.5

So 2300 >  2220.5. The area you want to build is bigger than the area available.

The city will not approve

7 0
3 years ago
Please help!!!!!!!!!!!!!!! i need this answer really fast!!!
yan [13]

Answer:

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2 years ago
Solve the equation 4n = 9
aliina [53]

Answer:

n = 9/4 = 2.250

Step-by-step explanation:

Rearrange:     4*n-(9)=0

Solve:  4n-9 = 0

     4n = 9

       n = 9/4 = 2.250

answer:     n = 9/4 = 2.250

6 0
4 years ago
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30/50 simply the fraction
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Th answer is 3/5. Divide by the GCF (10) to get 3/5
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Find the greatest common factor of 28a^5 46a^3
Tasya [4]
The answer to the question

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