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Brut [27]
3 years ago
10

The museum guide provides 10 brochures telling about the museum's history to each tourist group. If 12 groups visited today, how

many brochures were distributed?
Please help me
Mathematics
2 answers:
GenaCL600 [577]3 years ago
8 0

Answer:

It is 120 brochures distributed "I hope this helps"

Step-by-step explanation:

12x10=120

Rina8888 [55]3 years ago
3 0

Answer:

120

Step-by-step explanation:

just do 10*12 which is 120.

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[Please help] At the mall, Leona bought a T-shirt and a book for a total of $28. The book cost $12. How much did the T-shirt cos
podryga [215]

Answer:

the T-shirt cost is $16

Step-by-step explanation:

first, we know the total cost of the shirt and book was $28 so we substract 12 from 28 wich gives us 16 so the cost of the shirt is $16.

8 0
3 years ago
69. The O'Brien's had $400.0 in a special
charle [14.2K]

Hello :D

$40.00 x 3 = $120.00

$20.00 x 2 = $40.00

$120.00 + $40.00 = $160.00

$400.00 - $160.00 = $240.00

There is $240.00 left in the account.

5 0
3 years ago
I need help pls thank y
otez555 [7]
What do you need help with
5 0
3 years ago
Explain how to use mental math to express 12/25 as a percent
o-na [289]

Answer:

Step-by-step explanation:

12/25 =

12 ÷ 25 =

0.48 =

0.48 × 100/100 =

0.48 × 100% =

(0.48 × 100)% =

48%;

8 0
3 years ago
PLEASE PEOPLE, HELP ME!! Geometry
Oksanka [162]
I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

 now i use the the Law of Cosines 

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
3 years ago
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