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Cloud [144]
3 years ago
15

I will mark you brainiest and I will gave you 100 points to answer the question correctly A point is chosen in the circle at ran

dom. Determine which of the statements are true. Check all that apply.
It is unlikely the point is in region A.
It is likely the point is in region C.
It is likely the point is in region G.
It is impossible for the point to be in region H.
It is certain that the point will land in a lettered region.
I try C,D,E but I got wrong.

Mathematics
1 answer:
kaheart [24]3 years ago
7 0

Answer:

It is unlikely the point is in region A.

It is impossible for the point to be in region H.

It is certain that the point will land in a lettered region.

Step-by-step explanation:

Hope it helps!

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How do I find the slope of a perpendicular line?
Licemer1 [7]
Yes, math can be challenging sometimes (mostly due to the horrible way its taught by teachers but I wont go on a rant about that today).

The Slope of a parallel line is obviously going to have the same slope as the line it is parallel to, which you already know.

But for perpendicular, how would we figure that out?

First, you need to understand whats going on.  Picture a linear line.  Now, look at the (0,0) point.  To make it perpendicular, it must form 90 degrees with the other line.  Now, to get the answer for a perpendicular line, you need to remember two steps.

1.) Change the sign to the opposite sign (negative would go positive and positive would go negative)

2.) You take the reciprocal of the line (That is what times that number would make that number equal one.  2 * 1/2 would be 1.  You can also look at this by switching the denominator and numerator.

If you have more questions, feel friend to add me and write me<span />
4 0
3 years ago
Combine the following fractions by addition or subtraction as directed.
Marina86 [1]
Answer:\frac{6}{y^2-xy}-\frac{6}{x^2-xy}=\frac{6(x+y)}{xy(y-x)}

Explanation:

Combining the fractions, we have:

\begin{gathered} \frac{6(x^2-xy)-6(y^2-xy)}{(x^2-xy)(y^2-xy)} \\  \\ =\frac{6x^2-6xy-6y^2+6xy}{(x^2-xy)(y^2-xy)} \\  \\ =\frac{6x^2-6y^2}{x(x-y).y(y-x)} \\  \\ =\frac{6(x-y)(x+y)}{-xy(x-y)^2} \\  \\ =\frac{-6(x+y)}{xy(x-y)} \\  \\ =\frac{6(x+y)}{xy(y-x)} \end{gathered}

8 0
1 year ago
Susan was supposed to use 5/4 of a cup of butter
ElenaW [278]

Answer:

a.\ \dfrac{3}{5}

Step-by-step explanation:

We can see the fractions \frac{5}{4} and \frac{3}{4} of cups.

It can be seen that denominator has 4 i.e. the fraction \frac{1}{4}.

Let us suppose, a unit is equal to \frac{1}4 of a cup.

Susan was supposed to use \frac{5}{4} of a cup.

i.e. 5 units of butter was to be used.

But, actual recipe has only 3 units of butter.

\text{Fraction of butter used} = \dfrac{\text{Units of butter used}}{\text{Unit of butter Susan was supposed to use}}

a. \text{Fraction of butter used} = \dfrac{3}{5}

Alternatively, we could have directly divided the given fractions:

\dfrac{\dfrac{3}{4}}{\dfrac{5}{4}} = \dfrac{3}{5}

4 0
3 years ago
Solve for x and show all of your steps.<br> 3x - 20 - 4x = 4x - (3x - 2)
snow_tiger [21]
Answer: x = -11

Step-By-Step:
We can start by combining like terms on the left side.
-20 - x = 4x - (3x - 2)
Now we need to distribute the negative on the right side.
-20 - x = 4x - 3x + 2
Now combine like terms on the right.
-20 - x = x + 2
Now add 20 to the other side
- x = x + 22
Subtract x from the left side.
-2x = 22
Now divide by -2.
x = -11
6 0
3 years ago
Read 2 more answers
Can anybody answer this? Please! I’ll mark you brainliest
labwork [276]

Problem 1: Plug in the given value into the function and evaluate.

f(x)=|3x|\\f(2)=|3(2)|\\f(2)=|6|\\f(2)=6

Problem 2: Solve the equation for y.

-7x+2y=8

add 7x to both sides to move it to the right side of the equation.

2y=7x+8

Divide both sides of the equation by 2 to get a single y variable on the left hand side.

\frac{2y}{2} =\frac{7x}{2} +\frac{8}{2} \\y=\frac{7}{2}x+4

Simplify the terms to get the the equation into slope-intercept form.

The slope of the line is \frac{7}{2}

I'm a unsure what Problem 3 is asking for sorry I hope the rest is helpful.

5 0
3 years ago
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