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Cloud [144]
3 years ago
15

I will mark you brainiest and I will gave you 100 points to answer the question correctly A point is chosen in the circle at ran

dom. Determine which of the statements are true. Check all that apply.
It is unlikely the point is in region A.
It is likely the point is in region C.
It is likely the point is in region G.
It is impossible for the point to be in region H.
It is certain that the point will land in a lettered region.
I try C,D,E but I got wrong.

Mathematics
1 answer:
kaheart [24]3 years ago
7 0

Answer:

It is unlikely the point is in region A.

It is impossible for the point to be in region H.

It is certain that the point will land in a lettered region.

Step-by-step explanation:

Hope it helps!

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Simplify the expression.
ivann1987 [24]

Answer:

x

Step-by-step explanation:

(log to the base 3) of 27^x can be re-written as

x*(log to the base 3) of 27, which is equivalent to:

x*(log to the base 3 of 3^3)  =  x

So the answer is simply " x "

8 0
3 years ago
What is the lest comen demomator of 1/8 1/12 and 7/18
Bond [772]

Answer:

72

Step-by-step explanation:

18*4

12*6

8*9

5 0
3 years ago
Read 2 more answers
First five problems
jonny [76]

Answer:

1. B

3. C

4. B

5. What r the angles?

Step-by-step explanation:

Sry... I dont think I'm able to do #2 bc I'm only in Algebra I but there u go ;)

4 0
3 years ago
For the function Y=5x, what would happen if the value 5 was changed to 3
Daniel [21]

Answer:

y = 3 * x

Step-by-step explanation:

We have the function y = 5 * x, they ask us what would happen if we change the 5 by the 3. thus:

y = 3 * x

the constant that accompanies x in this case is an increase or slope constant, that is, now x will not increase by a ratio of 5, but by a ratio of 3. For example:

If x were worth 10

the value before was 50 and now it will be 30.

I do not increase 5 times but 3 times.

4 0
4 years ago
Find the number of steel ball bearings, each of diameter 0.7 cm, that can be made from 1kg of steel, given that 1cm cubed of ste
liq [111]

Answer:

Ball Bearing Volume = (4 / 3) * PI * radius ^3

Volume = (4 / 3) * 3.14159265 * (.35)^3

Volume = (4 / 3) * 3.14159265 * 0.042875

Volume = 0.17959438 cc

1 cc of steel = 7.8 g

Volume of 1 kg of steel = 1,000 cc / 7.8 g per cc

1 kg = 128.205 cc

Number of ball bearings we can make = 128.205 / 0.17959438

Equals 713.86

Step-by-step explanation:

7 0
3 years ago
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