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ololo11 [35]
3 years ago
5

What is the hafe way number between 12 and 34 i need this anwer asap

Mathematics
1 answer:
timama [110]3 years ago
6 0
23 is the middle number from 12 to 34.
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Please help!
nasty-shy [4]
Right change flip it's simple
4 0
3 years ago
Which of the following is equal to the expression listed below?
Sliva [168]

Answer:

C. 9(3+2)

Step-by-step explanation:

9*3 = 27 and 9*2 = 18 then add which gives you 45

Or do it this way

9(3+2) = 9(5) = 45

Hope this helps!

3 0
3 years ago
Read 2 more answers
Expand the expression: 2.2(-4k + 1)
evablogger [386]

Answer:

8.8k + 2.2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
For a statistics class project, a college student randomly samples 75 men who exercise at a gym regularly and 68 women who exerc
raketka [301]

Answer:

iii. The data do not provide sufficient evidence to conclude that the mean number of minutes exercised per week is larger for men than for women at this gym

Step-by-step explanation:

1) The hypotheses are

H0: u1 ≤ u2 against the claim Ha: u1 > u2

The men spend less or equal time than the women  at the gym each week

vs

the men  spend greater time  than the women at the gym each week

2) The test statistic is

t= (x1`- x2`) / √ s1²/n1+ s2²/n2

t= 65.7- 64.8/√(13.9)²/75 + (9.6)²/68

t= 0.9/√2.57613 +1.35529

t=0.4539

and the degrees of freedom is

3) υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

=[(13.9)²/75 + (9.6)²/68]²/ [(13.9)²/75 ]² /74 + [ (9.6)²/68]²/67

= 139

The degrees of freedom is always rounded in this calculation

4) The Critical region is [1.656, ∞]

5) t-score is outside of the critical region, so there is not enough evidence to reject H₀.

iii. The data do not provide sufficient evidence to conclude that the mean number of minutes exercised per week is larger for men than for women at this gym

4 0
2 years ago
QUICK!! 18x^2+21x-60=0 pls give me the steps as well
Anton [14]

Answer:

<h2>x1 =  -  \frac{5}{2}</h2>

x2 =  \frac{4}{3}

Step-by-step explanation:

18 {x}^{2}  + 21x - 60 = 0

Divide both sides of the equation by 3

6 {x}^{2}  + 7x - 20 = 0

Write 7x as a difference

6 {x}^{2}  + 15x - 8x - 20 = 0

Factor out 3x from the expression

3x(2x + 5) - 8x - 20 = 0

Factor out -4 from the expression

3x(2x + 5) - 4(2x + 5) = 0

Factor out 2x + 5 from the expression

(2x + 5)(3x - 4) = 0

When the product of factors equals 0 , at least one factor is 0

2x + 5 = 0

3x - 4 = 0

Solve the equation for X

2x + 5 = 0

Move constant to R.H.S and change its sign

2x = 0 - 5

Calculate the difference

2x  =  - 5

Divide both sides of the equation by 2

\frac{2x}{2}  =  \frac{ - 5}{2}

Calculate

x 1=  -  \frac{5}{2}

Again,

3x - 4 = 0

Move constant to RHS and change its sign

3x = 0 + 4

Calculate the sum

3x = 4

divide both sides of the equation by 3

\frac{3x}{3}  =  \frac{4}{3}

Calculate

x 2=  \frac{4}{3}

Hope this helps..

Best regards!!

5 0
3 years ago
Read 2 more answers
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