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3 years ago

What are the solutions of 12 – x2 = 0?

2 answers:

4 0

$- {x}^{2} + 12 = 0 \\ - x {}^{2} + 12 - 12 = 0 - 12 \\ - {x}^{2} = - 12 \\ {x}^{2} = 12 \\ x = + \sqrt{12 \:} and - \sqrt{12}$

Kazeer [188]3 years ago

4 0

Answer:

x = 2√3 and -2√3

Step-by-step explanation:

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2 years ago

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each of equal sides of an isosceles triangle is 4cm greater than its height .If the base of triangle is 24 cm ,calculate the per

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<h3>Answer:-</h3>

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<h3>Step by step explanation :-</h3>

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