Question

What are the solutions of 12 – x2 = 0?

Answer 1

$- {x}^{2} + 12 = 0 \\ - x {}^{2} + 12 - 12 = 0 - 12 \\ - {x}^{2} = - 12 \\ {x}^{2} = 12 \\ x = + \sqrt{12 \:} and - \sqrt{12}$

Answer 2

Answer:

x = 2√3 and -2√3

Step-by-step explanation: