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kenny6666 [7]
2 years ago
7

During an annual end-of-year performance review, a team of realtors reported the number of homes sold that year. The histogram s

hows those sales results. Which of the following statements are true about the home sales data set represented by this histogram? Select all that apply.

Mathematics
1 answer:
frutty [35]2 years ago
8 0

Answer:

There were 7 realtors who sold at least 40 homes

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H(x)=4x+3<br> Domain: all real number<br> Find range
CaHeK987 [17]

don't know if this might help but here

Step-by-step explanation:

(−∞,∞),{y|y∈R}

4 0
2 years ago
Simplify the expression. 6(7n – 5m) + 8m
borishaifa [10]
6(7n – 5m) + 8m
42n - 30m + 8m
42n -22m
Answer: 42n-22m

7 0
3 years ago
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A 26-foot long ladder is leaning against a building at a 60 degree angle with the ground. Which of the following equations can y
Sati [7]

Answer:

22.5 feet (to the nearest tenth).

Step-by-step explanation:

The equations have not been given but still the question can be solved. The ladder lying with a building makes a right angled triangle, in which the ladder is the hypotenuse, the building is the perpendicular, and the ground is the base. The length of the ladder (hypotenuse) is 26 feet and the angle with the ground is 60 degrees. The required length to be found is the length of the building (perpendicular). So the following formula will be used:

sin θ = Perpendicular/Hypotenuse.

Substituting in the equation gives:

sin60 = p/26.

p = 26*sin60.

p = 22.5 (to the nearest tenth).

The approximate height of the building is 22.5 feet!!!

4 0
3 years ago
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Find the radius of the circle with equation x²+y²+8x+8y+28=0
galina1969 [7]
<h2>Hello!</h2>

The answer is:

Center: (-4,-4)

Radius: 2 units.

<h2>Why?</h2>

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where:

"h" and "k" are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

x^{2}+y^{2}+8x+8y+28=0

So, solving we have:

x^{2}+y^{2}+8x+8y=-28

(x^2+8x+(\frac{8}{2})^{2})+(y^2+8y+(\frac{8}{2})^{2})=-28+((\frac{8}{2})^{2})++(\frac{8}{2})^{2})\\\\(x^2+8x+16 )+(y^2+8y+16)=-28+16+16\\\\(x^2+4)+(y^2+4)=4

(x^2-(-4))+(y^2-(-4))=4

Now, we have that:

h=-4\\k=-4\\r=\sqrt{4}=2

So,

Center: (-4,-4)

Radius: 2 units.

Have a nice day!

Note: I have attached a picture for better understanding.

3 0
3 years ago
The difference between 13 and a number k in algebraic expression?
viva [34]
13-k

Explanation: it’s just 13 minus the number k
8 0
3 years ago
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