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3 years ago

Learn with an example

Mathematics

1 answer:

stellarik [79]3 years ago

7 0

Answer:

Obtuse

Step-by-step explanation:

because 121

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kate buys 10 ticket to show. She also pays a 5$ parking fee. she spent $35 to see the show. What equation is this

Over [174]

Answer:

35 = 5 + 10x

Step-by-step explanation:

x = the ticket price.

Each ticket was $3

hope this helps :)

5 0

3 years ago

Read 2 more answers

Approximately 14 percent of the population of Arizona is 65 years or older. A random sample of five persons from this population

Andreas93 [3]

Answer:

A)0.8533

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are 65 or older, or they are not. The probability of a person being 65 or older is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

14 percent of the population of Arizona is 65 years or older.

This means that $p = 0.14$

A random sample of five persons from this population is taken.

This means that $n = 5$

The probability that less than 2 of the 5 are 65 years or older is :

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.14)^{0}.(0.86)^{5} = 0.4704$

$P(X = 1) = C_{5,1}.(0.14)^{1}.(0.86)^{4} = 0.3829$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.4704 + 0.3829 = 0.8533$

So the correct answer is:

A)0.8533

3 0

3 years ago

Solve for x. (e^x-e^-x)/((e^x+e^-x)=t

Sergio [31]

$\dfrac{e^x-e^{-x}}{e^x+e^{-x}}=t\\\\
\dfrac{e^{2x}-1}{e^{2x}+1}=t\\\\
e^{2x}-1=t(e^{2x}+1)\\\\
e^{2x}-1=e^{2x}t+t\\\\
e^{2x}-e^{2x}t=t+1\\\\
e^{2x}(1-t)=t+1\\\\
e^{2x}=\dfrac{t+1}{1-t}\\\\
e^{2x}=-\dfrac{t+1}{t-1}\\\\
2x=\ln\left(-\dfrac{t+1}{t-1}\right)\\\\
x=\dfrac{\ln\left(-\dfrac{t+1}{t-1}\right)}{2}\qquad t\in(-1,1)



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