Answer:
To equal the height of the Gateway Arch in St. Louis, it would take <u>76810 half dollars.
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Explanation:
If the Gateway Arch in St. Louis is 630 feet high, how many half dollars will it take to equal the height if each half dollar is 2.15mm thick?
First, we convert the ft to cm and the cm to mm.
- 1 ft = 30.48 cm
630 ft = 19202.4 cm
- 19202.4 cm = 192024 mm
Now, if a half dollar is 2.15 mm thick, how many half dollars would it take to equal the height of 192024 mm?
1 half dollar = 2.15 mm
X = 192024 mm
X = 192024 mm / 2.15 mm
X = 76810 half dollars.
<h3><u>Answer and explanation</u>;</h3>
- To balance the charges of ions the number of electrons lost is equal to the number of electrons gained. The overall net charge must be zero.
- The number of ions needed to accomplish this is represented by the subscripts.
- For any given ionic compound, the product of the charge on the ion (or multiatomic ionic group) times the subscript of the ion will give a total charge of zero when all ions are considered.
For examples: NaCl Na = +1 Cl = -1 total is zero
To find the wavelength of an electromagnetic wave for the given frequency can be determined by using the formulaSpeed=Wavelength x FrequencyWavelength=Speed/FrequencyGenerally Speed of the electromagnetic wave is 3x10^8 m/sBy substituting the values Wavelength=3x10^8 m/s / 2.63x10^12 s^-1Wavelength=1.14 x 10^-4 metres
Manufacturing A Drill That Can Be Used To Drill For Energy Sources At The Bottom Of The Ocean.
Explanation:
I may be correct but I give good luck to you- ^w
the balanced equation for the above reaction is as follows;
3NiCl₂ + 2K₃PO₄ ---> Ni₃(PO₄)₂ + 6KCl
stoichiometry of NiCl₂ to K₃PO₄ is 3:2
the number of NiCl₂ moles reacted - 0.0102 mol/L x 0.134 L = 0.00137 mol
according to molar ratio
if 3 mol of NiCl₂ reacts with 2 mol of K₃PO₄
then 0.00137 mol of NiCl₂ reacts with - 2/3 x 0.00137 = 0.000911 mol of K₃PO₄
molarity of given K₃PO₄ solution - 0.205 M
there are 0.205 mol in 1000 mL
therefore volume of 0.000911 mol - 0.000911 mol / 0.205 mol/L = 4.44 mL
volume of K₃PO₄ needed is 4.44 mL
