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katrin2010 [14]
3 years ago
5

Calculate the heat evolved kJ for the reaction of 1.00 g of elemental sulfur.

Chemistry
1 answer:
4vir4ik [10]3 years ago
3 0

Answer: Calculate the heat evolved (per mo SO2) for the reaction of sulfur with oxygen to form SO . Calculate the heat evolved from a reaction mixture of 13.4L SO at 1 ATM and 273K ... N-2 (g) + Os (g) → 2 NO (g) H = +180.6 kJ.

Explanation: I hoped that was helpful!

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the atomic mass of N is 14.01 g/mol and the atomic mass of H is 1.008 g/mol. what is the molecular mass of NH3
nikdorinn [45]
Molecular mass= (14.01∗1)+(1.008∗3)
                         14.01+3.024=17.03g/mol
7 0
3 years ago
An isotope will lose nucleons,protons,or neutrons in order to become more
Debora [2.8K]
Many atoms if they are radioactive isotopes will loss protons and neutrons as radiation in order to gain and become more stable 

hope that helps
8 0
3 years ago
Read 2 more answers
What is the maximum mass of aluminum chloride that could be obtained from 6 mol of barium chloride?
kodGreya [7K]
You have to find the stoichiometric ratio between AlCl₃ and BaCl₂. The common element between them is Cl. So, the ratio of Cl in BaCl₂ to AlCl₃ is 2/3. The molar mass of AlCl₃ is 133.34 g/mol. The solution is as follows:

Mass of AlCl₃ = (6 mol BaCl₂)(2 mol Cl/1 mol BaCl₂)(1 mol AlCl₃/3 mol Cl)(133.34 g/mol) = 533.36 g AlCl₃
8 0
3 years ago
A sample of food containing 27 g of fat, 48 g of carbohydrates and 20 g of protein is burned in a bomb calorimeter. In a perfect
rosijanka [135]

Answer:

38.3958 °C  

Explanation:

As,

1 gram of carbohydrates on burning gives 4 kilocalories  of energy

1 gram of protein on burning gives 4 kilocalories  of energy

1 gram of fat on burning gives 9 kilocalories of energy

Thus,

27 g of fat on burning gives 9*27 = 243 kilocalories of energy

20 g of protein on burning gives 4*20 = 80 kilocalories  of energy

48 gram of carbohydrates on burning gives 4*48 = 192 kilocalories  of energy

Total energy = 515 kilocalories

Using,

Q=m_{water}\times C_{water}\times (T_f-T_i)

Given: Volume of water = 23 L = 23×10⁻³ m³

Density=\frac{Mass}{Volume}  

Density of water= 1000 kg/m³

So, mass of the water:  

Mass\ of\ water=Density \times {Volume\ of\ water}  

Mass\ of\ water=1000 kg/m^3 \times {0.023\ m^3}  

Mass of water  = 23 kg

Initial temperature = 16°C  

Specific heat of water = 0.9998 kcal/kg°C  

515=23\times 0.9998\times (T_f-16)

Solving for final temperature as:

<u>Final temperature = 38.3958 °C  </u>

8 0
3 years ago
The molecular mass of a substance refers to the:
ololo11 [35]

Answer:

A

Explanation:

it's the sum of the masses of all the atoms in the molecule

please like and Mark as brainliest

3 0
3 years ago
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