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RUDIKE [14]
3 years ago
8

A beaker contains 175.32g of salt, NaCl(58.44g/mol). Water is added until the final volume is 2 liters. The solution should be d

escribed as
A. 87.66M

B. 29.22M

C. 3M

D. 1M

E. 1.5M
Chemistry
1 answer:
cricket20 [7]3 years ago
8 0

Answer:

E. 1.5M

Explanation:

because there is total 175.32 g of NaCl dissolved in 2 liter of water, and 58.44 g = 1 mol

so total miles = 175.32/58.32 = 3 moles

now 3 moles are in 2 liter of water, hence one liter contains 3/2= 1.5

Therefore answer is E. 1.5M

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love history [14]

Answer:

m=1.325gNa_2CO_3

Explanation:

Hello,

In this case, by considering the given seminormal solution, we infer it is a 0.5-N solution which means that we can obtain the equivalent grams as shown below for the 55 cc (0.055 L) volume:

eq-g=0.5eq-g/L*0.050L=0.025eq-g

Next, since sodium carbonate has two sodium ions with a +1 oxidation state each, we can obtain the moles:

mol=0.025eq-gNa_2CO_3*\frac{1molNa_2CO_3}{2eq-gNa_2CO_3}\\ \\mol=0.0125molNa_2CO_3

Finally, the mass is computed by using its molar mass (106 g/mol)

m=0.0125molNa_2CO_3*\frac{106gNa_2CO_3}{1molNa_2CO_3} \\\\m=1.325gNa_2CO_3

Regards.

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Explanation: hope that helps

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if im wrong correct me but have a blessed day/night

=)


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