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Thepotemich [5.8K]
3 years ago
9

Help anyone can help me do this question,I will mark brainlest.​

Mathematics
1 answer:
Goshia [24]3 years ago
7 0

Answer:

10. x is 15; y is \sqrt104. 11. \sqrt5

Step-by-step explanation:

for 10:

first we find the face on the left side; which according to the pythagorean theorem x is 144 + 81 =225 = x = 15. and y is 11^2 + y^2 = 225 = 225 - 121 = y^2 = y = the square root of 104.

for 11:

144 + y^2 = 169 = y^2 = 25 = y = 5. because the two sides are equivalent, the base is also 5 for the left part of the triangle. therefore, 5^2 + 5^2 = x^2 which means x is the square root of 5.

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What is the image point of (8, 4) after a translation left 2 units and down 4 units?
tino4ka555 [31]

Answer:

(6, 0 )

Step-by-step explanation:

A translation to the left means subtract 2 from the x- coordinate

A translation down means subtract 4 from the y- coordinate

Then

(8, 4 ) → (8 - 2, 4 - 4 ) → (6, 0 )

5 0
3 years ago
Read 2 more answers
Find the coordinates of the point where the line <img src="https://tex.z-dn.net/?f=y%3D5x%2B7%5C%5C" id="TexFormula1" title="y=5
Anvisha [2.4K]

Answer:

(0, 7)

Step-by-step explanation:

The point that crosses the y-axis is called the y-intercept of the line.

We are given an equation of the line and we need to determine the y-intercept. This can be done by determining the constant in the equation.

What are constants?

Constants are such terms that include only numbers. There should be no variables in constants.

<u>We know that:</u>

     \bullet \ \text{Given equation of line: y = 5x + 7}

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7 0
2 years ago
-5/2a+ 5=25...............,....................................
sveta [45]

\text{Hey there!}

\mathsf{-\dfrac{5}{2}a+5=25}

\text{\bf{SUBTRACT}}\mathsf{\ by\ 5\ on\ your\ sides}\\\mathsf{-\dfrac{5}{2}a+5-5=25-5}\\\\\mathsf{Cancel\ out: 5-5\ because\ it\ gives\ you\ 0}\\\\\mathsf{Keep: 25 - 5\ because\ it\ helps\ us\ solve\ for\ a}\\\\\mathsf{25-5=20}\\\\\mathsf{New\ equation:- \dfrac{5}{2}a=20}

\text{\bf{MULTIPLY}}\mathsf{\  \dfrac{2}{-5}\ on\ your\ sides}\\\\\mathsf{\dfrac{2}{=5}\times\dfrac{-5}{2}a=\dfrac{2}{-5}\times20}\\\\\mathsf{Cancel\ out: \dfrac{2}{-5}\times\dfrac{-5}{2}\ because\ it\ gives\ you\ 1}\\\\\mathsf{Keep: \dfrac{2}{-5}\times20\ because\ it\ gives\ you\ the\ value\ of\ a}\\\\\mathsf{\dfrac{2}{-5}\times20=-8}

\boxed{\boxed{\boxed{\boxed{\mathsf{Thus\ your\ answer\boxed{\boxed{\mathsf{a=-8}}}}}}}}\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\dfrac{\frak{LoveYourselfFirst}}{:)}

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