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Nata [24]
3 years ago
15

Find the volume of the given rectangular pyramid. 16 cm 10 cm 4 cm

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
7 0
The answer is 10 cent
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AHHH I just wanna know if what I put on the table is right ;-;​
vfiekz [6]

Yeah you did well on the table

3 0
4 years ago
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199228384838393940404093499494+18283764656453=? Pls help
german

Answer:

the answer is =1.9922838483839398e+29

Step-by-step explanation:

hoped I helped:)

3 0
3 years ago
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The solution is {-8, 3} but I’m not sure how to graph it on a line, is it A B C or D?
shtirl [24]

Answer:

-8 < x< 3

Step-by-step explanation:

|2x+5| <11

there are two solutions, one positive and one negative ( remember to flip the inequality for the negative)

2x+5 <11  and   2x+5 > -11

Subtract 5 from each side

2x+5-5 < 11-5 and    2x+5-5 > -11-5

2x< 6           and           2x>-16

Divide by 2

2x/2 <6/2        and       2x/2 >-16/2

x <3                  and             x>-8

-8 < x< 3

x is less than 3 and x is greater than -8

open circles and -8 and 3 and a line between

8 0
3 years ago
Perform the indicated operations on the following complex numbers. Simplify:<br> -6(3 + 5i)
Nat2105 [25]
All you can do is distribute out the -6
To get:
-18+ -30i
4 0
3 years ago
A stone is dropped into a lake, creating a circular ripple that travels outward at a speed of 70 cm/s. Find the rate at which th
jeyben [28]

Answer:

(A) 30772cm^2/s

(B) 153860cm^2/s

(C) 184632 cm^2/s

Step-by-step explanation:

We are given

speed of the ripple = 70cm/s

this speed is increasing the radius which means speed = radius /time

radius = speed*time

r= 70t

Now we know the area of the circle

A = πr^2

this area will be increasing as ripples in water will spread out

upon differentiating

dA/dt = 2πr * \frac{dr}{dt}

dA/dt = 2π*70t*70       ( r= 70t , dr/dt = speed = 70)

dA/dt = 9800π*t

(A) after 1 second

dA/dt = 9800π*1=9800π = 30772cm^2/s

(B) after 5 seconds

    dA/dt = 9800π*5 = 153860cm^2/s

(C) after 6 seconds

 dA/dt = 9800π*6 = 184632 cm^2/s

4 0
3 years ago
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